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3 years ago

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If a car travels 30 mi. north for 30 min., 60 mi. east for 1.0 hour, and 30 mi. south for 30 min., what is the average speed of

the car over the first two legs of the trip? 60 mph 50. mph 53 mph 53.3 mph

1 answer:

dexar [7]3 years ago

5 0

A) 30 mi. north for 30 min - 15 miles traveled

B) 60 mi. east for 1.0 hour - 60 miles traveled

75 miles traveled for 1.5 hours = 50 mph

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Nookie1986 [14]

Answer:

$\large\boxed{y=\dfrac{1}{4}x^2-x-4}$

Step-by-step explanation:

The equation of a parabola in vertex form:

$y=a(x-h)^2+k$

<em>(h, k)</em><em> - vertex</em>

The focus is

$\left(h,\ k+\dfrac{1}{4a}\right)$

We have the vertex (2, -5) and the focus (2, -4).

Calculate the value of <em>a</em> using $k+\dfrac{1}{4a}$

<em>k = -5</em>

$-5+\dfrac{1}{4a}=-4$ <em>add 5 to both sides</em>

$\dfrac{1}{4a}=1$ <em>multiply both sides by 4</em>

$4\!\!\!\!\diagup^1\cdot\dfrac{1}{4\!\!\!\!\diagup_1a}=4$

$\dfrac{1}{a}=4\to a=\dfrac{1}{4}$

Substitute

$a=\dfrac{1}{4},\ h=2,\ k=-5$

to the vertex form of an equation of a parabola:

$y=\dfrac{1}{4}(x-2)^2-5$

The standard form:

$y=ax^2+bx+c$

Convert using

$(a-b)^2=a^2-2ab+b^2$

$y=\dfrac{1}{4}(x^2-2(x)(2)+2^2)-5\\\\y=\dfrac{1}{4}(x^2-4x+4)-5$

<em>use the distributive property: a(b+c)=ab+ac</em>

$y=\left(\dfrac{1}{4}\right)(x^2)+\left(\dfrac{1}{4}\right)(-4x)+\left(\dfrac{1}{4}\right)(4)-5\\\\y=\dfrac{1}{4}x^2-x+1-5\\\\y=\dfrac{1}{4}x^2-x-4$

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Answer: The answer would be 8.

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3 years ago

Find the vertex of the function h(x) = x2 – 4x – 21

lakkis [162]

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Step-by-step explanation:

The x coordinate of the vertex is $x=-\frac{-4}{2(1)}=2$ .

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2 years ago

I'm awful at word problems someone please help

Lubov Fominskaja [6]

Your answer is B.

Flat fee is $250, so we cannot change this number.
585 - 250 = 335
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The maximum number of students a school can send is 41.

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M AR = 55°
m RB = 66°
Like AB=8 m =RS →m RS = m AB

m AB = m AR + m RB
m AB = 55° + 66°
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m RS = m AB
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Answer: m RS is 121°

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4 years ago

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