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Zepler [3.9K]
4 years ago
7

If f(x)= 4^-8 and g(x)= 5x+6, find (f-g)(x)

Mathematics
1 answer:
Sveta_85 [38]4 years ago
5 0

f(x)=4^x-8,\ g(x)=5x+6\\\\(f-g)(x)=f(x)-g(x)=(4^x-8)-(5x+6)=4^x-8-5x-6=4^x-5x-14

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Please show your work! Thankyou!
ZanzabumX [31]
Log₄(y+2) = 3, transform it into exponent form:

(y+2) = 4³
y+2 = 64
 y= 62

5 0
3 years ago
Expansion Numerically Impractical. Show that the computation of an nth-order determinant by expansion involves multiplications,
posledela

Answer:

  • number of multiplies is n!
  • n=10, 3.6 ms
  • n=15, 21.8 min
  • n=20, 77.09 yr
  • n=25, 4.9×10^8 yr

Step-by-step explanation:

Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...

  mpy[n] = n·mp[n-1]

  mpy[2] = 2

So, ...

  mpy[n] = n! . . . n ≥ 2

__

If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...

  10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10

Then the larger matrices take ...

  n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min

  n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years

  n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years

_____

For the shorter time periods (less than 100 years), we use 365.25 days per year.

For the longer time periods (more than 400 years), we use 365.2425 days per year.

8 0
4 years ago
There is a rectangle with a length of 12.5x +5 and a width of 5 . What is the area of the triangle
krek1111 [17]
The answer would be 65
4 0
3 years ago
Please give me the correct answer.Only answer if you're very good at math.Please don't put a link to a website.​
Simora [160]

Answer:

3n + 75

Step-by-step explanation:

Multiply n by 3  = 3n

Multiply 25 by 3 = 75

7 0
3 years ago
Doug estimates that his soccer team will win 7 games this year. The team actually wins 10 games. What is the percent error of Do
baherus [9]

Answer: 30%

Step-by-step explanation:

Percent error = \dfrac{|\text{Estimated value - Actual value}|}{\text{Actual value}}\times100\%

Estimated number of games win this year = 7

Actual number of games won = 10

Now ,   the percent error of Doug’s estimate = \dfrac{|7-10|}{10}\times100\%= \dfrac{3}{1}\times10\%=30\%

Hence, the percent error of Doug’s estimate = 30%

6 0
3 years ago
Read 2 more answers
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