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AfilCa [17]
3 years ago
7

What is the 10th term in the geometric sequence: 32, 16, 8, 4...?

Mathematics
2 answers:
xeze [42]3 years ago
6 0
The tenth term is 0.0625.  All you have to do between each term is divide by two, so 36 (divided by two), 16 (divided by two), 8, 4, 2, 1, .5, .25, .125, .0625
pav-90 [236]3 years ago
3 0
Hi there
just keep dividing by 2 tell you get to the 10th term
that's one way of doing it
32, 16, 8, 4, 2, 1 , 1/2 , 1/4 , 1/16, 1/32
1/32 is the 10th term
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Find the volume of the triangular prism.
goldfiish [28.3K]

Answer:

V = 31.5 in ^3

Step-by-step explanation:

The volume is Bh

The base is the triangle

B = 1/2 (7) *2

B = 7 in^2

Now find the volume

V = 7* 4.5

V = 31.5 in ^3

5 0
4 years ago
Please answer this question!
Aleks [24]
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3 years ago
Burnwood Tech plans to issue some $50 par preferred stock with a 8% dividend. A similar stock is selling on the market for $65.
Vanyuwa [196]

Answer:

6.5%

Step-by-step explanation:

The formular used to calculate the cost of preferred stock is:

= Fixed dividend/Net proceeds

Fixed dividend= $50 × 8/100

= $50×0.08

=$4

Net proceeds= Market price-Flotation costs

= $65-(6/100×$65)

= $65-(0.06×$65)

= $65-3.9

= $61.1

Therefore cost of preferred stock is

= 4/61.1 ×100

= 0.065×100

= 6.5%

Hence the cost of preferred stock is 6.5%

8 0
3 years ago
For the functions f(x) and g(x), determine the domain of (f ∙ g)(x) (the product of f and g).
Luba_88 [7]

Answer: Domain: (-∞, 0) U (0, ∞)

Step-by-step explanation:

\frac{12}{x} *-8x^{3}

=-96x^2

Domain: (-∞, 0) U (0, ∞)

7 0
2 years ago
(a) find parametric equations for the line of intersection of the planes x + y + z = 2 and x + 7y + 7z = 2
nlexa [21]
Direction vector of line of intersection of two planes is the cross product of the normal vectors of the planes, namely
p1: x+y+z=2
p2: x+7y+7z=2

and the corresponding normal vectors are: (equiv. to coeff. of the plane)
n1:<1,1,1>
n2:<1,7,7>

The cross product n1 x n2
vl=
 i  j  l
1 1 1
1 7 7
=<7-7, 1-7, 7-1>
=<0,-6,6>
Simplify by reducing length by a factor of 6
vl=<0,-1,1>

By observing the equations of the two planes, we see that (2,0,0) is a point on the intersection, because this points satisfies both plane equations.

Thus the parametric equation of the line is
L: (2,0,0)+t(0,-1,1)
or
L: x=2, y=-t, z=t

3 0
3 years ago
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