Answer:
Step-by-step explanation:
a )
probability of a computer being ancient = .99
probability of a computer being cutting-edge =.01
probability of two selected computer being old
= .99 x .99
= .98 or 98%
b )
probability of 5 selected computers being old
= .99 x .99 x .99 x .99 x .99
= .95 or 95%
c )
probability that at least one of the five selected computers is cutting-edge
= 1 - probability of 5 selected computers being old
= 1 - .95
= .05
5 %
Answer:
There are no solutions
Step-by-step explanation:
4/5 ( 20x + 5 ) = 16x - 2
Distibute on the left:
( 4/5 x 20 x ) + ( 4/5 x 5 ) = 16x - 2
16x + 4 = 16x - 2
Subtract 16x from both sides:
4=-2
Add 2 to each side:
6=0
No solutions
The answer is expressions D, E, and G.
In algebra, a ‘term’ usually means the different parts of an expression that are separated by + and - signs.
Options A and B only have 1 term, an x or y³, so these are incorrect.
Option C has 1 term as well, ‘xyz’, because they are all multiplied together which makes it one term.
D and E both have 3 terms each, but F has 4 unique terms so this is incorrect also.
G has 3 unique terms, x³, x^4, and 7x, so this is correct.
When H is expanded, you will end up with more than 3 unique terms, so this is incorrect.
I hope this helps!
Answer:
The number of chicken and cows should be 19 and 11.
Step-by-step explanation:
The number of chicken and cows should be 19 and 11.
Given that,
The farm has 30 chickens and cows, and there are 82 chicken and cow legs all together.
Let x represent the number of chickens in the farm.
Let y represent the number of cows in the farm.
Based on the above information, the calculation is as follows:
x + y = 30
Since a chicken has 2 legs and a cow has 4 legs.
So,
2x + 4y = 82 - - - - - - - - - - - - 1
Now
Substituting x = 30 - y into equation 1, it becomes
2(30 - y) + 4y = 82
60 - 2y + 4y = 82
- 2y + 4y = 82 - 60
2y = 22
y = 11
Now
x = 30 - 11
= 19
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