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Afina-wow [57]
3 years ago
14

Twice a number increased by 3 is 45. What is the number?

Mathematics
2 answers:
Arada [10]3 years ago
7 0
135 because 45x3=135 at least I'm sure this is what you mean
irinina [24]3 years ago
5 0

2N+3=45

2N = 42

N = 42/2 = 21

N = 21

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Please HELP I WILL REWARD BRAINLIEST ANSWER IM VERY CONFUSED
ozzi
Dilation is either : enlargement or shirking.

Simply you multiply the ordered pair times the dilation vector (Origin-Centered) 

D.F = dilation factor;


d.f  = 5

C' = d.fC

when you multiply a constant times an ordered pair , it multiples into each of the pair.


C' = 5 ( -5 , 1 ) = ( -25, 5 ) 

In case you were asked for A' , B' (test yourself before checking) 



A' = 5 (-4,3) = ( -20 , 15)

B' = 5 ( 2, 3 ) = ( 10, 15) 

Dividing the dilated by the original pair results in the dilation factor

A'/A =  (-20/15)/(-4,3) = 5(-4,3)/(-4,3) = 5 
4 0
3 years ago
If you don't want to expose<br> yourself to the sun, you should
ipn [44]

Answer:

Uhm well you can use sunscreen or a nice hat

Step-by-step explanation:

8 0
3 years ago
Stefanie is painting her bedroom. She can paint 12 1/3 square feet in 1/5 of an hour. How many square feet can she paint in one
Mnenie [13.5K]

Answer:

37

Step-by-step explanation:

8 0
3 years ago
Nate and Maya are building model cars. Maya's car is 3 inches less than 2 times the length of Nate's car. The sum of the lengths
Leni [432]

Answer:

Option D.) x + 2x − 3 = 26

Step-by-step explanation:

Let

x ------> the length of Nate's car

y ------> the length of Maya's car

we know that

x+y=26 -----> equation A

y=2x-3 ----> equation B

substitute equation B in equation A and solve for x

x+(2x-3)=26

3x=26+3

x=29/3 in

Find the value of y

y=2(29/3)-3

y=(58/3)-3

y= 49/3 in

4 0
3 years ago
Read 2 more answers
Help.........................<br><br>​
garri49 [273]
<h3>Answer: Choice A</h3>

x^2\left(\sqrt[4]{x^2}\right)

=====================================================

Explanation:

The fourth root of x is the same as x^(1/4)

I.e,

\sqrt[4]{x} = x^{1/4}

The same applies to x^10 as well

\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4}

Multiply the exponents 10 and 1/4 to get 10/4

\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4} = x^{10*1/4} = x^{10/4}

\sqrt[4]{x^{10}} = x^{10/4}

-----------------------

If we have an expression in the form x^(m/n), with m > n, then we can simplify it into an equivalent form as shown below

x^{m/n} = x^a\sqrt[n]{x^b}

The 'a' and 'b' are found through dividing m/n

m/n = a remainder b

'a' is the quotient, b is the remainder

-----------------------

The general formula can easily be confusing, so let's replace m and n with the proper numbers. In this case, m = 10 and n = 4

m/n = 10/4 = 2 remainder 2

We have a = 2 and b = 2

So

x^{m/n} = x^a\sqrt[n]{x^b}

turns into

x^{10/4} = x^2\sqrt[4]{x^2}

which means

\sqrt[4]{x^{10}} = {x^2} \sqrt[4]{x^2}

7 0
3 years ago
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