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pogonyaev
3 years ago
8

Python - Please help!

Computers and Technology
1 answer:
Margaret [11]3 years ago
6 0

Answer:

i= 1

for i in range(1,n):

     if i * i < n:

           print(2* i + 1)

     i += 1

else:

     print('Hakuna Matata')

Explanation:

First, there's a need to rewrite the code segment in your question (because of indentation)

<em>i= 1</em>

<em>while i*i < n:</em>

<em>      print(2* i + 1)</em>

<em>      i += 1</em>

<em>else:</em>

<em>      print('Hakuna Matata')</em>

<em />

The explanation of the equivalent of the above while loop is as follows

This line initializes i to 1

i= 1

This line iterates from 1 to n-1

for i in range(1,n):

This line checks if i * i is less than n

     if i * i < n:

The following line is executed if the above condition is satisfied; otherwise, nothing is done

           print(2* i + 1)

The value of i is incremented by 1 using this line

     i += 1

The following is executed at the end of the iteration

else:

     print('Hakuna Matata')

<em>Note: Assume any value of n, both programs display the same output</em>

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// program in C++.

#include <bits/stdc++.h>

using namespace std;

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// read number

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Wrong input!!enter number between 20-98 only:12                                                                            

Wrong input!!enter number between 20-98 only:93                                                                            

The output is: 93 92 91 90 89 88

Enter the number between 20 and 98: 77                                                                                    

The output is: 77

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