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Mumz [18]
3 years ago
5

What is another name for a blue screen error which occurs when processes running in kernel mode encouter a problem and windows m

ust stop the system?
Computers and Technology
1 answer:
Sonbull [250]3 years ago
7 0
Another name for a blue screen error is Blue screen of death
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3 years ago
Write a method called removeHighPrice that will go through a provided ArrayList called prices and removes the first price that i
Diano4ka-milaya [45]

Answer:

The method written in Java is as follows:

public static ArrayList<Double> removeHighPrice (ArrayList<Double> prices){

       for(int i =0;i<prices.size();i++){

     if(prices.get(i) > 5.00){

         prices.remove(i);  

         break;

     }

 }

 return(prices);  

 }

Explanation:

This line declares the method

public static ArrayList<Double> removeHighPrice (ArrayList<Double> prices){

This line iterates through the ArrayList named prices

       for(int i =0;i<prices.size();i++){

This checks if current price is greater than 5

     if(prices.get(i) > 5.00){

If yes, the price is removed

         prices.remove(i);  

And the loop is terminated

         break;

     }

 }

This returns the ArrayList

 return(prices);  

 }

<em>I've added as an attachment, the complete program which includes the main method</em>

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6 0
3 years ago
Implement a recursive method named power that takes 2 integer parameters named base and expo. The method will return the base ra
nika2105 [10]

Answer:

def power(base, expo):

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Explanation:

*The code is in Python.

Create a method called power that takes base and expo as parameters

Check if the expo is equal to 0. If it is return 1 (This is our base case for the method, where it stops. This way our method will call itself "expo" times). If expo is not 0, return base * power(base, expo-1). (Call the method itself, decrease the expo by 1 in each call and multiply the base)

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mrs_skeptik [129]

Answer:

import java.io.*;

public class Larger {

  public static void main(String[] args) throws IOException{

       BufferedReader br=new BufferedReader(new InputStreamReader(System.in));// reading input from buffered reader

        int a,max=-99999,i;

        for(i=1;i<=5;i++)

        {

            a=Integer.parseInt(br.readLine());//converting string input string to int

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        }

       System.out.println("Maximum value : "+max);

  }

Explanation:

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