Answer:
0.0073 < 0.05, which means that we reject the null hypothesis and conclude that the true proportion of interest is higher than 0.7.
Step-by-step explanation:
Conduct a test to determine whether the true proportion of interest is higher than 0.7.
This means that the null hypothesis is: ![H_{0}: p = 0.7](https://tex.z-dn.net/?f=H_%7B0%7D%3A%20p%20%3D%200.7)
And the alternate hypothesis is: ![H_{a}: p > 0.7](https://tex.z-dn.net/?f=H_%7Ba%7D%3A%20p%20%3E%200.7)
The test statistic is:
![z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}](https://tex.z-dn.net/?f=z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D)
In which X is the sample mean,
is the value tested at the null hypothesis,
is the standard deviation and n is the size of the sample.
0.7 is tested at the null hypothesis:
This means that ![\mu = 0.7, \sigma = \sqrt{0.7*0.3}](https://tex.z-dn.net/?f=%5Cmu%20%3D%200.7%2C%20%5Csigma%20%3D%20%5Csqrt%7B0.7%2A0.3%7D)
The sociologist found that 375 of the 500 travelers randomly selected and interviewed indicated that the airports were safe.
This means that ![n = 500, X = \frac{375}{500} = 0.75](https://tex.z-dn.net/?f=n%20%3D%20500%2C%20X%20%3D%20%5Cfrac%7B375%7D%7B500%7D%20%3D%200.75)
Value of the z-statistic:
![z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}](https://tex.z-dn.net/?f=z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D)
![z = \frac{0.75 - 0.7}{\frac{\sqrt{0.7*0.3}}{\sqrt{350}}}](https://tex.z-dn.net/?f=z%20%3D%20%5Cfrac%7B0.75%20-%200.7%7D%7B%5Cfrac%7B%5Csqrt%7B0.7%2A0.3%7D%7D%7B%5Csqrt%7B350%7D%7D%7D)
![z = 2.44](https://tex.z-dn.net/?f=z%20%3D%202.44)
P-value of the test:
Probability of z being larger than 2.44, that is, a proportion larger than 0.75.
This is, looking at the z-table, 1 subtracted by the pvalue of Z = 2.44. S
Z = 2.44 has a pvalue of 0.9927
1 - 0.9927 = 0.0073
0.0073 < 0.05, which means that we reject the null hypothesis and conclude that the true proportion of interest is higher than 0.7.