The surface area of the pyramid is 576.
<em>The square base is 144. It's just a square, so you multiply 12 (length) and 12 ( width) , which equals 144. </em>
<em>Then you find the area of one of the triangles. The equation to find triangles goes like this: 0.5 x B (base: 12) x H (height: 18). That would be 6 x 18 which is 108.</em>
<em>Since you got the area of 1 triangle and there are 4 triangles you have to multiply 108 by 4. That'll give you 432.</em>
<em>SO since you have the area of all the triangles and the square base the last thing you have to do is just add it all up. </em>
<em>The area of the triangles plus the area of the square base = the surface area.</em>
<u>432 cm + 144 cm =576 cm.</u>
Answer:
5^6
Step-by-step explanation:
by the law of exponents,
5^2 * 5^(-8)
5^ [2+ (-8)]
5^(2-8) = 5^-6 = 1/5^6 = 5^6
Answer:
Option C
Step-by-step explanation:
From the question we are told that
Co-ordinate of school A =(7,12)
Co-ordinate of school B =(-21,-13)
Generally the sum of the vector is mathematically represented
Generally the actual distance between the schools is mathematically given as
Answer:
(0, -8)
Step-by-step explanation:
The distance must be equal from C to A and points B to D.
Answer:
Option 1:(x-4)^2+y^2=100
Step-by-step explanation:
Given center = (h,k) = (4,0)
The point (-2,8) lies on circle which means the distance between the point and center will be equal to the radius.
So,
The distance formula will be used:
Hence radius is 10.
The standard form of equation of circle is:
(x-h)^2+(y-k)^2 = r^2
Putting the values
(x-4)^2+(y-0)^2=10^2
(x-4)^2+y^2=100
Hence option 1 is correct ..