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yarga [219]
3 years ago
8

3 - 3 × 6 + 2 = ? So what -13 or -17 or 0 ;-)

Mathematics
2 answers:
olga2289 [7]3 years ago
8 0
3-3×6+2= 3-18+2= -15+2= -13
DENIUS [597]3 years ago
6 0
;)

We\ will\ use\ PEMDAS.

Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

We\ do\ the\ multiplication\ and\ division\ first\ as\ there\ are\ no\\
parenthesis\ and\ exponents\ in\ the question.
\\3 - 3\times6 + 2 =\\ 3 - 18 + 2 =\\ Now\ we\ just\ add\ and\ subtract\ what\ is\ left.\ :)\\ \fbox{We\ go\ from\ left\ to\ right.}\\ 3 - 18 = -15\\ -15 + 2 = -13\\ \\ The\ answer\ is\ \fbox{-13}.
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Could you help plz.​
I am Lyosha [343]

Cost of each bags of flour = $2.50

Cost of each bags of butter = $3.75

Solution:

Let f be the bags of flour and b be the pounds of butter.

Cost of 20 bags of flour 16 pound of butter = 110

⇒ 20f + 16b = 110 -------------------- (1)

Cost of 30 bags of flour 12 pound of butter = 120

⇒ 30f + 12b = 120  -------------------- (2)

Equation (1) and (2) are the system of equations.

(2) ⇒ 30f + 12b = 120

Subtract 30f from both sides.

⇒ 12b = 120 – 30f

Divide by 12 on both sides.

$\Rightarrow b =\frac{120-30f}{12}  -------------------- (3)

Substitute (3) in (1).

$20f+16\left(\frac{120-30f}{12}\right)=110

$20f+4\left(\frac{120-30f}{3}\right)=110

$20f+4(40-10f)=110

$20f+160-40f=110

Subtract 160 from both sides.

$-20f=-50

Divide by –20, we get

$f=\frac{5}{2}

f = 2.50

Substitute f = 2.5 in equation (3), we get

$\Rightarrow b =\frac{120-30(2.50)}{12}

$b=\frac{15}{4}

b = 3.75

Cost of each bags of flour = $2.50

Cost of each bags of butter = $3.75

7 0
3 years ago
For this exercise assume that all matrices are ntimesn. Each part of this exercise is an implication of the form​ "If "statement
inna [77]

Answer:

C. True; by the Invertible Matrix Theorem if the equation Ax=0 has only the trivial solution, then the matrix is invertible. Thus, A must also be row equivalent to the n x n identity matrix.

Step-by-step explanation:

The Invertible matrix Theorem is a Theorem which gives a list of equivalent conditions for an n X n matrix to have an inverse. For the sake of this question, we would look at only the conditions needed to answer the question.

  • There is an n×n matrix C such that CA=I_n.
  • There is an n×n matrix D such that AD=I_n.
  • The equation Ax=0 has only the trivial solution x=0.
  • A is row-equivalent to the n×n identity matrix I_n.
  • For each column vector b in R^n, the equation Ax=b has a unique solution.
  • The columns of A span R^n.

Therefore the statement:

If there is an n X n matrix D such that AD=​I, then there is also an n X n matrix C such that CA = I is true by the conditions for invertibility of matrix:

  • The equation Ax=0 has only the trivial solution x=0.
  • A is row-equivalent to the n×n identity matrix I_n.

The correct option is C.

5 0
3 years ago
Question 19: Please help. What is the equation of the line, in slope-intercept form, that is perpendicular to the line with the
alukav5142 [94]

Answer:

the first optionnnnnnn

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3 years ago
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bogdanovich [222]

Answer:

6.86

Step-by-step explanation:

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2 years ago
4|6-8| absolute value
sveta [45]
I think it’s 8 ( I’m not sure )
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