2f(x) = 2x - 4 [0, 3]3f(x) = 3x - 1 [-2, -1]9f(x) = x² [4, 5]4f(x) = 4x [5, 20]5f(x) = x² - 3 [0, 5]1f(x) = x + 10 [-5, -1]10f(x) = 10x [-3, 0]¹/₂f(x) = 0.5x - 2 [2, 4]11f(x) = 2x² + x [1, 4]-1f(x) = -x + 2 [-3, 5]Domainthe set of all reasonable input values of x for the functionRangeset of output y values for the domain of the functionAverage Rate of ChangeChange in values over a given interval.Origin(0,0) on the coordinate graphing system; where the two axes meetx-axisthe horizontal number line in the coordinate systemy-axisthe vertical number line in the coordinate systemCoordinatesany specific (x,y) in the coordinate systemx-interceptwhere the function intersects the x-axisy-interceptwhere the function intersects the y-axis; the b value in a linear functionLinear FunctionA function whose graph is a straight line, where the average rate of change (slope) is constant.Exponential FunctionA function where the average rate of change is not constant and whose input value is an exponent.Table of ValuesA table showing two sets of related numbers<span>Slope of line through the points (-2, 3) and (0,0)
m = (0 - 3) / (0 - -2) = -3/2</span><span>Average Rate of Change on the interval
[-2, 0]</span>Slope: m = "rise over run" = 2Rate of Change<span>Slope of line through the points (5, -1) and (0,0)
m = (0 - -1) / (0 - 5) = -1/5</span><span>Average Rate of Change on the interval
[0, 5]</span><span>Slope of line through the points
(0, 16) and (4, 21)
m = (21 - 16) / (4 - 0) = 5/4</span>Average Rate of Change over the interval [0,4]
-4y - x - (3y - 9x)...distribute the - thru the parenthesis
-4y - x - 3y + 9x....now combine like terms
8x - 7y <== or -7y + 8x
Answer:
Step-by-step explanation:
We are given the following in the question:
The needle size should not be too big and too small.
The diameter of the needle should be 1.65 mm.
We design the null and the alternate hypothesis
Sample size, n = 35
Sample mean, 
= 1.64 mm
Sample standard deviation, s = 0.07 mm
Type I error:
- It is the error of rejecting the null hypothesis when it is true.
- It is also known as false positive error.
- It is the rejecting of a true null hypothesis.
Thus, type I error in this study would mean we reject the null hypothesis that the average diameter is 1.65 mm but actually the average diameters of the needle is 1.65 mm.
Thus, average diameter is 1.65 mm and we decide that it is not 1.65 mm.
Answer:
Hello,
If Mr. Trujilo wants to pain only the wall:
Wall:
12.5 feet x 8.5 feet = 106.25 ft2
Door
5 feet x 6.75 feet = 33.75 ft2
Wall - Door = 106.25 ft2 - 33.75 ft2 = 72.5 ft2
Answer:
y = 30x + 20
Step-by-step explanation:
y = mx + b
find b
b=20
find m
m=30
