Solve for t. s=1/2gt^2
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Mr. Jackson invested $800 at 6% per year and $ 2400 at 4 % per year
<h3><u>Solution:</u></h3>Mr. Jackson invested a sum of money at 6% per year, and 3 times as much at 4% per year.
Let the sum invested be ‘a’ and ‘3a’ at 6% per year and 4 % per year respectively
Also, his annual return totaled $144
We can form following equation on the basis of question:-
a = $800
The amount of money invested at 6% = a = 800
The amount of money invested at 4 % = 3a = 3(800) = 2400
So, the amount of money invested at 6% is $800 and the amount of money invested at 4% is $ 2400
Basically if you have an exponent at the end of a 10, 
, then in the end the extended notation is going to have 7 zeros. So it'll be 10000000. Then you multiply whats in the rest of the equation together. There's the beginning :) I hope it helps.