Answer:
Y=7+3x, x=-3, y=-2
Step-by-step explanation:
3x-5y=1. Equation 1
3x-y=-7. Equation 2
-y=-7-3x isolate for y in equation 2
y=7+3x multiplied by -1 to get positive y
3x-5(7+3x)=1 substitute y value of equation 2 (7+3x) into equation 1
3x-35-15x=1
-12x=36
x=-3
solve for y.
3x-5y=1
3(-3)-5y=1
-9-5y=1
-5y=10
y=-2
Mr. Jackson invested $800 at 6% per year and $ 2400 at 4 % per year
<h3><u>Solution:</u></h3>
Mr. Jackson invested a sum of money at 6% per year, and 3 times as much at 4% per year.
Let the sum invested be ‘a’ and ‘3a’ at 6% per year and 4 % per year respectively
Also, his annual return totaled $144
We can form following equation on the basis of question:-

a = $800
The amount of money invested at 6% = a = 800
The amount of money invested at 4 % = 3a = 3(800) = 2400
So, the amount of money invested at 6% is $800 and the amount of money invested at 4% is $ 2400
Basically if you have an exponent at the end of a 10,

, then in the end the extended notation is going to have 7 zeros. So it'll be 10000000. Then you multiply whats in the rest of the equation together. There's the beginning :) I hope it helps.
It’s the last one. (X+2)2+(x+372-1/2)