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3 years ago

0.051x40(0.5+0.01)x40 using distributive property

Mathematics

1 answer:

krek1111 [17]3 years ago

4 0

Answer:

41.616

Step-by-step explanation:

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Which represents the solution(s) of the equation x2 = 36?

mart [117]

Answer:

Step-by-step explanation:

x2 = 36?

solution

x^2-(36)=0

Factoring: x2-36

Check : 36 is the square of 6

Check : x2 is the square of x1

Factorization is : (x + 6) • (x - 6)

(x + 6) • (x - 6) = 0

x+6 = 0

x = -6

x-6 = 0

add 6 to both side

x = 6

x = -6

7 0

3 years ago

Read 2 more answers

NEED HELP QUCKILY PLZ HURRY

Romashka-Z-Leto [24]

Hello from MrBillDoesMath!

Answer:

Discussion:

Parallel lines cut by a transversal has corresponding angles equal. . So the corresponding angles x and (3x-70) are equal. That is,

x = 3x - 70 => add 70 to both sides

x + 70 = 3x => subtract x from both sides

70 = 3x - x = 2x => divide both sides by 2

x = 70/2 = 35

which is the third choice

Thank you,

MrB

7 0

3 years ago

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Find the whole. 140% of____ is 56.<br><br><br> for homework i need help asap

lianna [129]

Answer:

Step-by-step explanation:

140 percent (calculated percentage %) of what number equals 56? Answer: 40.

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3 years ago

Which expression represents (3x^2y^4) (4xy^2)

Natalka [10]

Answer: 12x^3 y^6

Step-by-step explanation: Have a nice day! -Lily ^-^

5 0

3 years ago

Let represent the number of tires with low air pressure on a randomly chosen car. The probability distribution of is as follows.

Sindrei [870]

Answer:

a) $P(X=3) = 0.1$

b) $P(X\geq 3) =1-P(X$

And replacing we got:

$P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4$

c) $P(X=4) = 0.3$

d) $P(X=0) = 0.2$

e) $E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2$

f) $E(X^2)= \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4$

And the variance would be:

$Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4$

And the deviation:

$\sigma =\sqrt{2.4} = 1.549$

Step-by-step explanation:

We have the following distribution

x 0 1 2 3 4

P(x) 0.2 0.3 0.1 0.1 0.3

Part a

For this case:

$P(X=3) = 0.1$

Part b

We want this probability:

$P(X\geq 3) =1-P(X$

And replacing we got:

$P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4$

Part c

For this case we want this probability:

$P(X=4) = 0.3$

Part d

$P(X=0) = 0.2$

Part e

We can find the mean with this formula:

$E(X)= \sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2$

Part f

We can find the second moment with this formula

$E(X^2)= \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4$

And the variance would be:

$Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4$

And the deviation:

$\sigma =\sqrt{2.4} = 1.549$

4 0

3 years ago