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Pachacha [2.7K]
4 years ago
15

I don’t understand how to do this

Mathematics
1 answer:
Simora [160]4 years ago
3 0
It's looking for the measures

m<F + m<G = 180°

(4x)° + (8x)° = 180°

12x = 180°
÷12 ÷12


x = 15

check your work

m<F + m<G = 180°

(4x)° + (8x)° = 180°

4(15)° + 8(15)° = 180°

60° + 120° = 180°
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X2<br> -<br> 1<br> In<br> Out<br> 5<br> 9<br> -3<br> -7<br> 7<br> -20
DerKrebs [107]

Answer:

|4| = |7|

this is the answer of this question

4 0
3 years ago
Evaluate 5^28·5^-32·5^-4<br> A. 17,920<br> B. 0.017920<br> C. 0.000256<br> D. 0.00000256
romanna [79]

Answer:

D 0.00000256

Step-by-step explanation:

5^{28} *5^{-32}*5^{-4}=5^{28-32-4}=5^{-8}=\frac{1}{5^{8}} =0.00000256

4 0
3 years ago
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Morgarella [4.7K]
Hope this helps u.!!!

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4 years ago
I need help almost ASAP!!! 1-5
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3 years ago
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Is each line parallel, perpendicular, or neither parallel nor perpendicular to the line −3x+5y=−15? Drag and drop each choice in
nexus9112 [7]

The first line is perpendicular, the second line is not perpendicular and not parallel , the third line is parallel to the above line and the forth line not parallel or perpendicular to the line.

<h3>How can the slope of the line be calculate?</h3>

The slope of the line  is been given as −3x+5y=−15

Then y= \frac{3}{5x} -3, hence the slope is \frac{3}{5}

  • Slope of the first line 5x + 3y = 15 after calculation is

the slope is y= \frac{5}{-3x} +5\\\\\frac{5}{-3}

this means that the line is perpendicular to the given line

  • Slope of the second line  3x + 5y = 15 after calculation is

y= \frac{3}{-5x} +15\\\\\frac{3}{-5}

This means that the line is not perpendicular and not parallel

  • Slope of the Third line  -3x + 5y = 15 can be calculated as

y= \frac{3}{5x} +15\\\\\frac{3}{5}

This means that the line is parallel to the above line.

  • Slope of the first line  3x + 5y = 15 after calculation is

y= \frac{-3}{5x} +3\\\\\frac{-3}{5}

This means that the line is not parallel or perpendicular to the line

Learn more about slope of  line at:

brainly.com/question/3493733

#SPJ1

5 0
2 years ago
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