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suter [353]
4 years ago
13

Both circle A and circle B have a central angle measuring 50°. The area of circle A's sector is 36π cm2, and the area of circle

B's sector is 64π cm2. Which is the ratio of the radius of circle A to the radius of circle B?
Mathematics
1 answer:
Romashka-Z-Leto [24]4 years ago
6 0

Answer:

9/8 pi


Step-by-step explanation:


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Rectangle A has length 12 and width 8. Rectangle B has length 15 and width 10. Rectangle C has length 30 and width 15.
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there are 5 walnut trees currently in the park park workers will plant 8 more walnut trees today how many walnut trees will the
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3 years ago
Question 5: prove that it’s =0
mamaluj [8]

Answer:

Proof in explanation.

Step-by-step explanation:

I'm going to attempt this by squeeze theorem.

We know that \cos(\frac{2}{x}) is a variable number between -1 and 1 (inclusive).

This means that -1 \le \cos(\frac{2}{x}) \le 1.

x^4 \ge 0 for all value x. So if we multiply all sides of our inequality by this, it will not effect the direction of the inequalities.

-x^4 \le x^4 \cos(\frac{2}{x}) \le x^4

By squeeze theorem, if  -x^4 \le x^4 \cos(\frac{2}{x}) \le x^4

and \lim_{x \rightarrow 0}-x^4=\lim_{x \rightarrow 0}x^4=L, then we can also conclude that \im_{x \rightarrow} x^4\cos(\frac{2}{x})=L.

So we can actually evaluate the "if" limits pretty easily since both are continuous  and exist at x=0.

\lim_{x \rightarrow 0}x^4=0^4=0

\lim_{x \rightarrow 0}-x^4=-0^4=-0=0.

We can finally conclude that \lim_{\rightarrow 0}x^4\cos(\frac{2}{x})=0 by squeeze theorem.

Some people call this sandwich theorem.

6 0
3 years ago
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