Ask question

Ask question

All categories

3 years ago

10

Samantha sends her son, barry, to a preschool center on certain days. The cost of preschool is $45 per day along with a fixed mo

nthly charge of $70. Last month, samantha paid a total of $880 to the preschool center. Let d represent the number of days barry spent at the preschool center last month. Which equation represents this situation, and how many days did barry attend preschool last month?

2 answers:

Ipatiy [6.2K]3 years ago

5 0

45d+70=$880. $880-70=$810. 810/45=18

Anon25 [30]3 years ago

3 0

Answer:

<em>The equation is: $45d+70=880$ </em>

<em>Barry attended preschool for 18 days last month.</em>

Step-by-step explanation:

The number of days, Barry spent at the preschool center last month is $d$ .

The cost of preschool is $45 per day. So, the total cost for $d$ days $= \$45d$

Fixed monthly charge is $70.

So, <u>the total charge of last month</u> $= (45d+70)\ dollars$

Given that, Samantha paid a total of $880 to the preschool center last month.

So, the equation that represents the situation: $45d+70=880$

Solving the above equation, we will get........

$45d+70=880\\ \\ 45d=880-70\\ \\ 45d=810\\ \\ d=\frac{810}{45}=18$

So, Barry attended preschool for 18 days last month.

You might be interested in

Which expression represents the number 2i4−5i3+3i2+−81‾‾‾‾√ rewritten in a+bi form?

vichka [17]

Answer:

The expression $-1+14i$ represents the number $2i^4-5i^3+3i^2+\sqrt{-81}$ rewritten in a+bi form.

Step-by-step explanation:

The value of $i$ is $i=\sqrt{-1}[tex] or [tex]i^{2}=-1[\tex].Now [tex]i^{4}$ in term of $i^{2}[\tex] can be written as, [tex]i^{4}=i^{2}\times i^{2}$

Substituting the value,

$i^{4}=\left(-1\right)\times \left(-1\right)$

Product of two negative numbers is always positive.

$\therefore i^{4}=1$

Now $i^{3}$ in term of $i^{2}[\tex] can be written as, [tex]i^{3}=i^{2}\times i$

Substituting the value,

$i^{3}=\left(-1\right)\times i$

Product of one negative and one positive numbers is always negative.

$\therefore i^{3}=-i$

Now $\sqrt{-81}$ can be written as follows,

$\sqrt{-81}=\sqrt{\left(81\right)\times\left(-1\right)}$

Applying radical multiplication rule,

$\sqrt{ab}={\sqrt{a}}\sqrt{b}$

$\sqrt{\left(81\right)\times\left(-1\right)}={\sqrt{81}}\sqrt{-1}$

Now, $\sqrt{\left(81\right)=9$ and $\sqrt{-1}}=i$

$\therefore \sqrt{\left(81\right)\times\left(-1\right)}=9i$

Now substituting the above values in given expression,

$2i^4-5i^3+3i^2+\sqrt{-81}=2\left(1\right)-5\left(-i\right)+3\left(-1\right)+9i$

Simplifying,

$2+5i-3+9i$

Collecting similar terms,

$2-3+5i+9i$

Combining similar terms,

$-1+14i$

The above expression is in the form of a+bi which is the required expression.

Hence, option number 4 is correct.

5 0

3 years ago

Classify this triangle

bulgar [2K]

Answer:

Acute, equilateral

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Who can help me with this worksheet ASAP need it for my tomorrow and I have a lot of homework to do please someone help me

RUDIKE [14]

Answer:

5n square root 5
6 square root 6v
16ki square root 2
10m square root m
4p square root 5p
3pi square root 5

6 0

3 years ago

Evaluate the expression when a = 2.<br> a^2+7a+7

Galina-37 [17]

Answer:

25

Step-by-step explanation:

a² + 7a + 7

a = 2

Plug in the value of 2 for every occurance of a.

(2)² + 7(2) + 7

First, solve the exponent.

4 + 7(2) + 7

Now, multiply.

4 + 14 + 7.

Add.

25

This is your answer.

Hope this helps!

7 0

2 years ago

If x to the power of 2 equals 196 what does x equal

natulia [17]

Answer:

14

Step-by-step explanation:

<h2><u>Solve for x</u></h2>

<u /> $x^{2} = 196$

this can be solved by square rooting 196

$x = \sqrt{196}$

x = 14

<h3><u>the value for x is 14</u></h3>

3 0

2 years ago

Read 2 more answers