Answer:
The expression
represents the number
rewritten in a+bi form.
Step-by-step explanation:
The value of
is
in term of ![i^{2}[\tex] can be written as, [tex]i^{4}=i^{2}\times i^{2}](https://tex.z-dn.net/?f=i%5E%7B2%7D%5B%5Ctex%5D%20can%20be%20written%20as%2C%20%3C%2Fp%3E%3Cp%3E%5Btex%5Di%5E%7B4%7D%3Di%5E%7B2%7D%5Ctimes%20i%5E%7B2%7D)
Substituting the value,

Product of two negative numbers is always positive.

Now
in term of ![i^{2}[\tex] can be written as, [tex]i^{3}=i^{2}\times i](https://tex.z-dn.net/?f=i%5E%7B2%7D%5B%5Ctex%5D%20can%20be%20written%20as%2C%20%3C%2Fp%3E%3Cp%3E%5Btex%5Di%5E%7B3%7D%3Di%5E%7B2%7D%5Ctimes%20i)
Substituting the value,

Product of one negative and one positive numbers is always negative.

Now
can be written as follows,

Applying radical multiplication rule,


Now,
and 

Now substituting the above values in given expression,

Simplifying,

Collecting similar terms,

Combining similar terms,

The above expression is in the form of a+bi which is the required expression.
Hence, option number 4 is correct.
Answer:
Acute, equilateral
Step-by-step explanation:
Answer:
25
Step-by-step explanation:
a² + 7a + 7
a = 2
Plug in the value of 2 for every occurance of a.
(2)² + 7(2) + 7
First, solve the exponent.
4 + 7(2) + 7
Now, multiply.
4 + 14 + 7.
Add.
25
This is your answer.
Hope this helps!
Answer:
14
Step-by-step explanation:
<h2><u>Solve for x</u></h2>
<u />
this can be solved by square rooting 196

x = 14
<h3><u>the value for x is 14</u></h3>