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Nataly_w [17]
2 years ago
9

1. At the gym on Monday, Larry is told to up his weight on the bench-press by 15% from last week. Last week he was bench-pressin

g 200 pounds. How many pounds should he bench-press this week?​
Mathematics
1 answer:
QveST [7]2 years ago
3 0

Answer:

300 lbs

Step-by-step explanation:

We know that Larry bench pressed 200 lbs last week, and that he is supposed to increase by 15%. We know that any number times one is that same numbers. That means a number that is increaseing has to be greater than 1. So, we have to convert 15% into a decimal. That is 0.15. That plus one is 1.15. Now we just have to multiply 1.15 with 200. We get 300.

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The growth of 100 young trees near a river is given below. At most 50 yards from the river (Event Y) More than 50 yards from the
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Answer:

It is 91% more likely that the tree was atmost 500 yards from the river.

<h3>Step-by-step explanation:</h3>

We are given with distance and height of 100 young trees near a river.

From that table, in total there are 55 trees which grow more than 3 ft during the year.

And among those 55 trees, 50 trees are atmost 50 yards from river.

Hence it is ≈91% more likely that the tree was atmost 50 yards from the river.

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3 years ago
Find the distance between each pair points (-5,3) , (-4,-5)?
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3 years ago
Solve the problem. Use the Central Limit Theorem.The annual precipitation amounts in a certain mountain range are normally distr
bazaltina [42]

Answer:

0.8944 = 89.44% probability that the mean annual precipitation during 25 randomly picked years will be less than 112 inches.

Step-by-step explanation:

To solve this question, we use the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 109.0 inches, and a standard deviation of 12 inches.

This means that \mu = 109, \sigma = 12

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What is the probability that the mean annual precipitation during 25 randomly picked years will be less than 112 inches?

This is the p-value of Z when X = 112. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{112 - 109}{2.4}

Z = 1.25

Z = 1.25 has a p-value of 0.8944.

0.8944 = 89.44% probability that the mean annual precipitation during 25 randomly picked years will be less than 112 inches.

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3 years ago
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Answer:

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