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Paul [167]
3 years ago
5

When expressing the unit for work, which of the following is the correct choice?

Physics
1 answer:
hram777 [196]3 years ago
4 0
I need to write 20 characters but your answer is Joule
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Particles of m1 and m2 (m2&gt;m1) are connected by a line in extensible string passing over a smooth fixed pulley. Initially, bo
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Answer:

The velocity with which the mass will hit the floor is v_f = \sqrt{2(\dfrac{m_2-m_1}{m_2+m_1}) x.}

Explanation:

If the tension in the string is T, for m_1 we have

T- m_1g =m_1a,

and for the mass m_2

T -m_2g = -m_2a

From these equations we solve for a and get:

a =(\dfrac{m_2-m_1}{m_2+m_1}) g.

The kinematic equation

v_f^2 = v_0^2+2ax

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In our case

v_0 = 0 (the initial velocity of the particles is zero)

a =(\dfrac{m_2-m_1}{m_2+m_1}) g.

which gives us

v_f^2 = 2ax

v_f^2 =2(\dfrac{m_2-m_1}{m_2+m_1}) g

\boxed{v_f = \sqrt{2(\dfrac{m_2-m_1}{m_2+m_1}) x.} }

which is the velocity with which the mass m_2 will hit the floor.

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