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NISA [10]
3 years ago
11

you do not know how confused i am with this question, please put a little explanation to explain how you did it.

Mathematics
1 answer:
Irina18 [472]3 years ago
3 0

Answer:

x=2

Step-by-step explanation:

2x = 4  and your multiplying 2 times x so x would have to be equal to 2 time blank which equals 4

Hope it helps!

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(7^x)^y = 7 <br> What is x • y?
baherus [9]

Answer:

1

Step-by-step explanation:

It simplifies to 7^xy=7. That means that xy must equal 1 to make the equation true.

8 0
2 years ago
Given the two sets, which statement is true?
IRINA_888 [86]

Answer:

\large\boxed{A\subset B}

Step-by-step explanation:

A=\{1,\ 2\},\ B=\{1,\ 2,\ 3,\ 4\}\\\\A\subset B,\ \text{because all elements of the set A are the elements of the set B.}

5 0
3 years ago
Find the value of x in the solution to the system of equations shown.
blagie [28]
Substitute the value of y into the second equation
y = 14x - 6
y = -4x + 48

14x - 6 = -4x + 48
add 6 to both sides
14x = -4x + 54
add 4x to both sides
18x = 54
divide both sides by 18
x = 3

The option is B.) x = 3

Hope this helps!
7 0
3 years ago
Read 2 more answers
A radioactive substance is decaying exponentially. If there are initially 15 grams of the substance and after 3 hours there are
sukhopar [10]

Answer:

Ok, an exponential decay is written as:

P(t) = A*(1 - r)^t

Where A is the initial population, r is the rate of decay and t is the unit of time.

We know that the initial population is 15g

then:

P(t) = 15g*(1 - r)^t

And at t = 3hs, the populations is 5g

P(5h) = 5g = 15g*(1 - r)^5

5/15 = 1/3 = (1 - r)^5

(1/3)^(1/5) = (1 - r) = 0.8

Now, the half life time of the sustance is t = x, such that the population reduces to it's half:

P(x) = A/2 = 15g/2 = 7.5g

Then:

7.5g = 15g*0.8^x

7.5g/15g = 1/2 = 0.8^x

Now, remember that if we have:

a = b^x

then

x = ln(a)/ln(b)

ln(1/2)/ln(0.8) = x = 3,11 hours

3 0
3 years ago
For f(x) = x2 + 2x + 3, and g(x) = x2 + 5, Find F(g(2)).
Paraphin [41]

Answer:

f(g(2)) = 102

Step-by-step explanation:

f(x) and f(g(2))

As we can see, we can find g(2) and substitute this value into

f(x)=x² + 2x + 3 instead of x.

g(x) = x² + 5,  g(2) = 2² + 5 = 9

f(x)=x² + 2x + 3

f(9)=9² + 2*9 + 3= 102

5 0
3 years ago
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