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2 years ago

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Will give Brainliest. Hannah does push-ups in sets of 3. She did 10 sets of pushups today. Then her coach asked her to do 15 mor

e push-ups. How many push-ups did Hannah do today?

2 answers:

Natali5045456 [20]2 years ago

7 0

Answer:

She did 45 pushups

Step-by-step explanation:

Ilya [14]2 years ago

3 0

Answer:

the answer is 45

Step-by-step explanation:

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Select the correct answer.

katen-ka-za [31]

Answer: B

how close their measurements are to each other

Step-by-step explanation:

The students in a science class did not know the length of the board before taking turns to measure the length of a certain board.

The characteristic of their measurements that best indicates

their accuracy will be how close their measurements are to each other.

If the actual length is known before the carry out the measurements, there average value will be neccessarily to determine their accuracy.

Therefore, option B is the best option.

5 0

2 years ago

Erica uses 9 gallons of gas to drive 198 miles. How many miles can he drive using 1 gallon of gas?

lara31 [8.8K]

Answer:

198 / 9 = 22

Step-by-step explanation:

3 0

3 years ago

Blank plus blank times blank equals nine-teen

Bad White [126]

The answer is 5+4×2=19

7 0

2 years ago

Read 2 more answers

Suppose customers in a hardware store are willing to buy N(p) boxes of nails at p dollars per box, as given by the following f

AleksAgata [21]

Answer:

a) -15 unites per dollar

b) -12 units per dollar

c) -18 units per dollar

Step-by-step explanation:

We are given the following in the question:

$N(p) = 100-3p^2, 1\leq p \leq 4$

where N(p) is the number of boxes of nails at p dollars per box.

a) average rate of change of demand for a change in price from $2 to $3.

Average rate of change =

$\displaystyle\frac{N(3) -N(2)}{3-2}\\\\=\frac{100-3(3)^2-(100 - 3(2)^2)}{1}\\\\= -15\text{ units per dollar}$

b) instantaneous rate of change of demand when the price is $2

Instantaneous rate =

$N'(p) = \displaystyle\frac{d(N(p))}{dp} = -6p$

$N'(2) = -6(2) = -12$

The instantaneous rate of change of demand when the price is $2 is decreasing at 12 units per dollar.

c) instantaneous rate of change of demand when the price is $3

Instantaneous rate =

$N'(3) = -6(8) = -18$

The instantaneous rate of change of demand when the price is $3 is decreasing at 18 units per dollar.

4 0

2 years ago

A cone has radius 9 and a height 12. A frustum of this cone has height 4.

Anettt [7]

Answer:

Part A)

The lower base has a radius of 9 units, and the upper base has a radius of 6 units.

Part B)

5 units.

Part C)

75π or about 235.62 square units.

Step-by-step explanation:

Please refer to the figure below.

The cone has a radius of 9 units and a total height of 12 units.

A frustum of the cone has a height of 4 units.

Part A)

The lower radius of the frustum will simply be 9 units.

For the upper radius, we will use the properties of similar triangles. We will compare the smaller upper triangle to the overall larger triangle. This yields:

$\displaystyle \frac{12}{8}=\frac{9}{x}$

Solve for <em>x.</em> Simplify:

$\displaystyle \frac{3}{2}=\frac{9}{x}$

Cross-multiply:

$18=3x\Rightarrow x=6$

The upper base has a radius of 6 units.

Part B)

We can first find the total slant height of the entire cone. By using the Pythagorean Theorem, this yields that the total slant height is:

$SH^2=12^2+9^2$

Simplify:

$SH^2=225\Rightarrow SH=15\text{ units}$

Now, find the slant height of the upper cone:

$(SH_\text{cone})^2=8^2+6^2=100$

So:

$SH_\text{cone}=10$

Then the slant height of the frustum will be the cone subtracted from the total. Thus:

$SH_{\text{frustum}}=15-10=5\text{ units}$

Part C)

We can first find the lateral area of the entire cone. The lateral area is given by:

$LA=\pi r\ell$

The lateral area of the entire cone will be:

$LA=\pi (9)(15)=135\pi$

The lateral area of the upper cone will be:

$LA_\text{cone}=\pi(6)(10)=60\pi$

Then the lateral area of the frustum is:

$LA_\text{frustum}=135\pi-60\pi =75\pi\text{ units}^2\approx235.62\text{ units}^2$

5 0

2 years ago