The average atomic mass of her sample is 114.54 amu
Let the 1st isotope be A
Let the 2nd isotope be B
From the question given above, the following data were obtained:
- Abundance of isotope A (A%) = 59.34%
- Mass of isotope A = 113.6459 amu
- Mass of isotope B = 115.8488 amu
- Abundance of isotope B (B%) = 100 – 59.34 = 40.66%
- Average atomic mass =?
The average atomic mass of the sample can be obtained as follow:
Thus, the average atomic mass of the sample is 114.54 amu
Learn more about isotope: brainly.com/question/25868336
Energy = mass * specific heat * temperature change this is what u need to do
Answer:
navier
JAJDKEKWNEHSJJXIDJ (i need to do that so i can post the answer haha)
Additional oxygen
Explanation : H2O is two hydrogens and one oxygen not 2 hydrogens two oxygens
Answer: The correct option is:
Explanation:
In balanced chemical equation , mass of the reactants is always equal to the mass of the products.
This is the balanced equation because on both sides number of sodium and bromine atoms are same.
On the reactant side there are two sodium atoms and two bromine atoms
On the product side there are also two sodium atoms and two bromine atoms in NaBr.
Mass of reactants (here 2Na and )= Mass of products(here 2NaBr)
2(23u) + 2(79.9u) = 2(23u + 79.9u) = 205 u