In similar figures, the ratio between corresponding sides are the same.

Simplify the two to see that they are equal.
The top and bottom of the left fraction are divisible by 5.
The top and bottom of the right fraction are divisible by 7.

Of course, the dimensions of that third picture would have to be this fraction.
Let's test these answers.

⇒ A is not a solution

⇒
B is the solution
(divide the top and bottom by 6)
The second graph or the letter B
9514 1404 393
Answer:
14.1 years
Step-by-step explanation:
Use the compound interest formula and solve for t. Logarithms are involved.
A = P(1 +r/n)^(nt)
amount when P is invested for t years at annual rate r compounded n times per year.
Using the given values, we have ...
13060 = 8800(1 +0.028/365)^(365t)
13060/8800 = (1 +0.028/365)^(365t) . . . . divide by P=8800
Now we take logarithms to make this a linear equation.
log(13060/8800) = (365t)log(1 +0.028/365)
Dividing by the coefficient of t gives us ...
t = log(13060/8800)/(365·log(1 +0.028/365)) ≈ 0.171461/0.0121598
t ≈ 14.1
It would take about 14.1 years for the value to reach $13,060.
Answer:
15 students
Step-by-step explanation:
No. of boys students = No. of all students - No. of girls
no. of boys =50-15 = 35 boys
the boys that will play the match are 2/7 of boys = (2/7)x35 = 10 boys
and the girls that will play the match are 5 girls
so, no of students chosen to play = 5+10=15 students