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3 years ago

6

PLEASE HELP!!!!

2 answers:

yan [13]3 years ago

7 0

C. The area is increased by an area of 25

8x7=56
40x35=1400

1400/56=25

pshichka [43]3 years ago

5 0

Consider what the area is when a rectangle has a width of 8m and a length of 7m. The area is 8m x 7m, or 56m^2.

Now, multiple the length and width by 5 each, to produce a triangle with the dimensions of 40m and 35m. Multiply the two values together to get 1400m^2.

1400 / 56 = 25, so the area is increased by a factor of 25.

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adelina 88 [10]

Answer:

Step-by-step explanation:

A = L * W

A = 22

L = 2x + 1

W = 3x + 1

now we sub

22 = (2x + 1)(3x + 1)

22 = 6x^2 + 2x + 3x + 1

22 = 6x^2 + 5x + 1

6x^2 + 5x + 1 - 22 = 0

6x^2 + 5x - 21 = 0 <======part A

(3x + 7)(2x - 3) = 0

3x + 7 = 0 2x - 3 = 0

3x = -7 2x = 3

x = -7/3 x = 3/2

I believe that x = -7/3 is an extraneous solution because when u plug it into ur length and width u get a negative number....and I dont think the sides of ur rectangle have negative values, however, it does work in ur equation and it equals 22 when multiplied...so I am not 100% sure

length = 2x + 1.......2(3/2) + 1........3 + 1 = 4

width = 3x + 1......3(3/2) + 1......9/2 + 1......9/2 + 2/2 = 11/2 (or 5.5) meters <===

6 0

3 years ago

The distance between two points is 6_/6.One endpoint is (4,-1). It is known that the y-coordinate of the other endpoint is 9.

babunello [35]

The x-coordinate of the given endpoint will be " $x = 4 \pm 2\sqrt{29}$ ".

According to the question,

The end points are:

$(x_1,y_1) = (4,-1)$
$(x_2, y_2) = (x,9)$

Distance,

$6\sqrt{6}$

As we know,

The distance formula,

→ $Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

By substituting the values, we get

→ $6\sqrt{6} = \sqrt{(x-4)^2+(9+1)^2}$

→ $216= (x-4)^2+100$

→ $(x-4)^2 = 116$

→ $x-4 = \pm \sqrt{116}$

→ $x-4=\pm 2\sqrt{29}$

→ $x = 4 \pm 2\sqrt{29}$

Thus the above answer is right.

Learn more:

brainly.com/question/18310956

5 0

2 years ago

Consider the following data set with an even number of data

photoshop1234 [79]

I guess “1” is the minimum value

8 0

3 years ago

Spencer made a quilt for his cousin's doll. The quilt had a 7x7 array of different color square patches. If each patch is 1 3/4

Damm [24]

Answer:

$\frac{2401}{16}$ square inches

Step-by-step explanation:

Given:

The quilt made by Spencer had a 7×7 array of different color square patches such that each patch is $1\frac{3}{4}$ in long.

To find: the area of the whole quilt

Solution:

Side of each quilt = $7(\frac{3}{4})=7(\frac{7}{4})=\frac{49}{4}$

Quilt is in the form of a square such that area of square is given by $(side)^2$

Therefore, area of quilt = $(side)^2=(\frac{49}{4})^2 =\frac{2401}{16}$ square inches

3 0

3 years ago

A scientist need 10 L of a 20% acid solution for an experiment where she had only a 5% solution and a 40% solution to the neares

andrezito [222]

Answer:

Amount of 5% solution = 5.7 Litres

Amount of 40% solution = 4.3 Litres

Step-by-step explanation:

First, of all, let x be the amount of 5% solution used

Since, the scientist needs 10 L of solution, then;

Let 10 - x be the amount of 40% solution used

Now, we are told that she needs 10 L of a 20% acid solution.

This means that;

5%x + 40%(10 - x) = 20%(10).

Simplifying this gives;

0.05x + 0.40(10 - x) = 0.20 × 10

Expanding the bracket gives;

0.05x + 4 - 0.4x = 2

0.4x - 0.05x = 4 - 2

0.35x = 2

x = 2/0.35

x ≈ 5.7 litres

Thus, she will need to mix 5.7 liters of the 5% solution.

Since 10 - x be the amount of 40% solution used , then;

the amount of 40% solution = 10 - 5.7 = 4.3 litres

4 0

3 years ago