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3 years ago

Mr.fulton puts 3 on each tray. how many are on 4 trays?

Mathematics

2 answers:

ruslelena [56]3 years ago

5 0

12 bananas are on 4 trays

slamgirl [31]3 years ago

4 0

3X4=12
Your answer me is 12
Hope I helped!

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-4.8[6.3x-4.8]=-58.56

DENIUS [597]

Answer:

=2.6984126984

Step-by-step explanation:

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3 years ago

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How do i solve this as an inequality?<br>a. 2x+6 <14<br><br>please send a step by step!! :)

Y_Kistochka [10]

Answer:

2x+6<14

2x<14-6

2x<8

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3 years ago

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Find the generating function for the sequence 1,1,1,2,3,4,5,6,....

marin [14]

Answer:

$P(x)=\dfrac{1}{1-x}+\dfrac{x^3}{(1-x)^2} \quad \text{for} \mid x \mid < 1$ [/tex]

Step-by-step explanation:

The generating function of a sequence is the power series whose coefficients are the elements of the sequence. For the sequence

$1,1,1,2,3,4,5,6,...$

the generating function would be

$P(x)=1+x+x^2+2x^3+3x^4+4x^5+5x^6+...\\$

we can multiply P(x) by x to get

$xP(x)=x+x^2+x^3+2x^4+3x^5+4x^6+...$

Note that

$P(x)-xP(x)=1+(2x^3-x^3)+(3x^4-2x^4)+(4x^5-3x^5)+(5x^6-4x^6)+...\\ \\=1+x^3+x^4+x^5+x^6+...=1+x^3(1+x+x^2+x^3+x^4+...)$

which for $\mid x \mid < 1$ can be rewritten as

$(1-x)P(x)=1+\dfrac{x^3}{(1-x)} \quad \Rightarrow \\\\P(x)=\dfrac{1}{(1-x)}+\dfrac{x^3}{(1-x)^2}$

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3 years ago

Use the variable d to represent the unknown quantity. the product of 4 and the depth of the pool

natka813 [3]

This can be represented by the expression 4d.

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2 years ago

At the U.S open tennis championship a statistician keeps track of every serve that a player hits during the tournament. The mean

GarryVolchara [31]

Answer:

Step-by-step explanation:

Both 115 and 145 mph are above the mean. Draw a normal curve and mark these speeds. 115 mph is 1 standard deviation above the mean; 130 would be 2 standard deviations above the mean; and 145 would be 3 s. d. above it.

We need to find the area under the standard normal curve between 115 and 145. This is equivalent to the area under the standard normal curve between z = 1 and z = 3.

I used my TI-83 Plus calculator's DISTR function "normalcdf(" to calculate this area: normalcdf(1, 3) = 0.1573.

The area between z = 1 and z = 3 is 0.1573. In other words, the percentage of serves that were between 115 and 145 mph was 15.73%.

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3 years ago