Neptune's distance from the sun is d₁ = 4.503 x 10⁹ km.
Mercury's distance from the sun is d₂ = 5.791 x 10⁷ km.
Calculate the number of times d₁ is greater than d₂.

Answer: 7.7759 x 10⁻¹ times
Answer:
Angle J <em>is</em><em> </em><em>congruent</em><em> </em><em>to</em><em> </em>Angle G
Answer:
7
Step-by-step explanation:
Let the height of pyramid be h

v= 224
w= 8
l= 12
224=1/3(12)(8)(h)
224=32h
h=224/32
h=7
Answer:
D or 6.4
Step-by-step explanation:
-6.3*(-2) + 2(-2 - 1.1)
- 6.3 * - 2 = 12.6 Notice that the two minus signs become a +
(-2 - 1.1)= (-3.1) Multiply -3.1 * 2 = - 6.2
12.6 - 6.2 = 6.4
Answer:
See below.
Step-by-step explanation:
The addition method is a good choice in this case since you have x in one equation and -x in the other equation, and x and -x add to zero, eliminating x.
x - 5.5y = -14
-x + 2.6y = 8.2
Add the equations. x and -x ad to zero, eliminating x. Then solve for y.
-2.9y = -5.8
Divide both sides by -2.9
y = 2
Substitute 2 for y in the first original equation, and solve for x.
x - 5.5y = -14
x - 5.5(2) = -14
x - 11 = -14
x = -3
Solution: x = -3; y = 2
Since the coefficients of y in the two original equations are not opposites, the addition method would not be the best method to use to solve for y first.