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Alchen [17]
3 years ago
5

Which expression would be easier to simplify if you used commutative property to change the grouping?

Mathematics
2 answers:
Brrunno [24]3 years ago
8 0

Answer:

I think c

Sory if it is wrong

Step-by-step explanation:

just olya [345]3 years ago
4 0
A because it’s just pluss what makes it easier
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Fill in the table using this function rule.<br> y=4+2x<br> X Y<br> 5<br> 7<br> 9<br> 10
saul85 [17]

Step-by-step explanation:

given that y=4+2x

for x=5

y=4+2(5)

y=14

for x=7

y=4+2(7)

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for x=9

f(9)=4+2(9)

Y=22

for x=10

y=4+2(10)

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3 0
3 years ago
Read 2 more answers
What are the solutions of x^2-2x+5=0
sweet [91]

The solution of x^{2}-2 x+5=0 are 1 + 2i and 1 – 2i

<u>Solution:</u>

Given, equation is x^{2}-2 x+5=0

We have to find the roots of the given quadratic equation

Now, let us use the quadratic formula

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}  --- (1)

<em><u>Let us determine the nature of roots:</u></em>

Here in x^{2}-2 x+5=0 a = 1 ; b = -2 ; c = 5

b^2 - 4ac = 2^2 - 4(1)(5) = 4 - 20 = -16

Since b^2 - 4ac < 0 , the roots obtained will be complex conjugates.

Now plug in values in eqn 1, we get,

x=\frac{-(-2) \pm \sqrt{(-2)^{2}-4 \times 1 \times 5}}{2 \times 1}

On solving we get,

x=\frac{2 \pm \sqrt{4-20}}{2}

x=\frac{2 \pm \sqrt{-16}}{2}

x=\frac{2 \pm \sqrt{16} \times \sqrt{-1}}{2}

we know that square root of -1 is "i" which is a complex number

\begin{array}{l}{\mathrm{x}=\frac{2 \pm 4 i}{2}} \\\\ {\mathrm{x}=1 \pm 2 i}\end{array}

Hence, the roots of the given quadratic equation are 1 + 2i and 1 – 2i

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3 years ago
Solve for x. 11x – 19x = -16 x =
ludmilkaskok [199]
Your answer is simple, it's x = 0
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Determine the area under the standard normal curve that lies to the left of ​(a) upper z equals 0.02 comma ​(b) upper z equals n
Anuta_ua [19.1K]
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c) 0.35197
d) 0.040930

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3 years ago
Help me represent this easy equation: For every unit of X you must produce 3 of Y
Sergio [31]

Answer:

Okay the, 3 of Y by every unit of X. Simple.

Step-by-step explanation:

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