Answer:
Jake is 9, and Jake's dad is 43.
Step-by-step explanation:
Ok, let's start off by putting a variable for Jack's age, A.
We know that Jack's father is 2 less than 5 times, so we can write his as 5x -2.
Now let's make an equation:
52 = x + 5x - 2
We need to isolate the x-values so we need to add 2 on both sides:
54= x + 5x
No we need to add the like terms:
54 = 6x
Finally, we just divide by 6 on each side.
Now we know X = 9 but we're not done yet :)
So because Jake's dad is almost 5 times as much, we first multiply Jack's age by 5. We get 45 but we need to subtract 2 which leaves us with 43.
0.4(2x+1/2) = 3[0.2x-2]-4
0.8x+0.2 = 0.6x-6-4 Distribute it out
0.8x+0.2 = 0.6x-10 Combine like terms
0.2x = -10.2 Subtract 0.6x and 0.2 from both sides
x = -51 Multiply both sides by 5
Answer:
The correct options are;
1) Write tan(x + y) as sin(x + y) over cos(x + y)
2) Use the sum identity for sine to rewrite the numerator
3) Use the sum identity for cosine to rewrite the denominator
4) Divide both the numerator and denominator by cos(x)·cos(y)
5) Simplify fractions by dividing out common factors or using the tangent quotient identity
Step-by-step explanation:
Given that the required identity is Tangent (x + y) = (tangent (x) + tangent (y))/(1 - tangent(x) × tangent (y)), we have;
tan(x + y) = sin(x + y)/(cos(x + y))
sin(x + y)/(cos(x + y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y))
(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y))
(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y)) = (tan(x) + tan(y))(1 - tan(x)·tan(y)
∴ tan(x + y) = (tan(x) + tan(y))(1 - tan(x)·tan(y)
Answer:
0.6 seconds to 2.6 seconds
Step-by-step explanation:
From the graph the ball reaches 28 feet after 0.574 seconds
and doesn't fall below that until 2.614 seconds
0.574 rounded is 0.6 seconds
2.614 rounded is 2.6 seconds
Answer:
I and IV
Step-by-step explanation:
Since 1-sin(θ)² = cos(θ)², the given equation is equivalent to ...
√(cos(θ)²) = |cos(θ)| = cos(θ)
This will be true where the cosine is non-negative, in the first and fourth quadrants.
