<span>Fred and Ethel Mertz
</span>
Answer:
Please answer my question
Moles of CaBr2 = 5/molar mass of CaBr2
= 5/199.886
= 0.025 moles.
Hope this helps!
Answer:
177.3kg C₂₁H₄₄
Explanation:
Based on the chemical reaction:
C₂₁H₄₄ → 3C₂H₄ + C₁₅H₃₂
<em>Where 1 mole of C₂₁H₄₄ produce 3 moles of ethene, C₂H₄.</em>
<em />
To solve this question we need to determine the moles of ethene in 50.4kg. 1/3 these moles are the moles of C₂₁H₄₄ that must be added:
<em>Moles Ethene -Molar mass: 28.05g/mol-</em>
50.4kg = 50400g * (1mol / 28.05g) = 1796.8 moles of ethene
<em>Moles C₂₁H₄₄:</em>
1796.8 moles of ethene * (1 mol C₂₁H₄₄ / 3 mol C₂H₄) = 589.93 moles C₂₁H₄₄
<em>Mass C₂₁H₄₄:</em>
589.93 moles C₂₁H₄₄ * (296g / mol) = 177283g =
<h3>177.3kg C₂₁H₄₄</h3>
