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PIT_PIT [208]
2 years ago
15

Which is right pls right answers only the one thats right will get brailiest

Chemistry
2 answers:
bagirrra123 [75]2 years ago
6 0
Substitute to x for one of the answer choices !
Leviafan [203]2 years ago
5 0

Answer:

Explanation:

the last one thats all i know

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A sample of n2 effuses in 255 s. how long will the same size sample of cl2 take to effuse?
7nadin3 [17]
For this problem, we use Graham's Effusion Law to find out the rate of effusion of chlorine gas. The formula is as follows:

R₁/R₂ = √(M₂/M₁)

Let 1 be N₂ while 2 be Cl₂

255/R₂ = √(28/70.8)
Solving for R₂,
R₂ = 405.5 s

<em>Thus, it would take 405.5 s to effuse chlorine gas.</em>
4 0
3 years ago
Most substances become less dense as the temperature increases. Which substance is an exception to this rule
stealth61 [152]
The substance is water
6 0
3 years ago
Read 2 more answers
Given 7.40 g of butanoic acid and excess ethanol, how many grams of ethyl butyrate would be synthesized, assuming a complete 100
Dafna11 [192]
On complete conversion (100% yield) 9.75 g of ethyl butyrate will be produced. Below is the solution.....

4 0
3 years ago
Which of these describes a Mole in Chemistry?
olya-2409 [2.1K]

Answer: Thus the correct option is  D. All of the above describe a mole

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass in grams.

1 mole of every substance contains avogadro's number 6.023\times 10^{23} of particles.

Mole is the S.I unit for measuring the amount of substance. It is often used to measure large number of particles.

Thus the correct option is  D. All of the above describe a mole

5 0
2 years ago
Calculate the enthalpy change, ∆H in kJ, for the reaction H2O(s) → H2(g) + 1/2O2(g). Use the following information: : +279.9 kJ
Len [333]

Answer:

+ 291.9 kJ

Solution:

The equation given is as;

H₂O ₍s₎ → H₂ ₍g₎ + 1/2 O₂ ₍g₎ ΔH = ?

First, as we know the heat of formation of H₂O ₍l₎ is,

H₂ ₍g₎ + 1/2 O₂ ₍g₎ → H₂O ₍l₎ ΔH = - 285.9 kJ

Now, reversing the equation will reverse the sign of heat as,

H₂O ₍l₎ → H₂ ₍g₎ + 1/2 O₂ ₍g₎ ΔH = + 285.9 kJ

Also, we know that,

H₂O ₍s₎ → H₂O ₍l) ΔH = + 6.0 kJ

Now, adding last two equations,

H₂O ₍l₎ → H₂ ₍g₎ + 1/2 O₂ ₍g₎ ΔH = + 285.9 kJ

H₂O ₍s₎ → H₂O ₍l) ΔH = + 6.0 kJ

-----------------------------------------------------------------------------

H₂O ₍s₎ → H₂ ₍g₎ + 1/2 O₂ ₍g₎ ΔH = + 291.9 kJ

5 0
3 years ago
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