We are given
total number of friends =6
the cost of one admission is $9.50
now, we can find total cost for admission
total cost for admission= total number of friends*cost of one admission
total cost for admission=6*9.50
we are given
cost for one ride on the Ferris wheel is $1.50
now, we can find total cost for Ferris wheel ride
total cost for Ferris wheel ride= total number of friends*cost of one ride
total cost for Ferris wheel ride=6*1.50
now, we can find total cost
total cost =total cost for admission+total cost for Ferris wheel ride
total cost
now, we can solve it
total cost
total cost
total cost
so, the total cost is $66...........Answer
This is a problem of Permutations. We have 3 cases depending on the number of B's. Since no more than three B's can be used we can use either one, two or three B's at a time.
Case 1: Five A's and One B
Total number of letters = 6
Total number of words possible = 
Case 2: Five A's and Two B's
Total number of letters = 7
Total number of words possible = 
Case 3: Five A's and Three B's
Total number of letters = 8
Total number of words possible = 
Total number of possible words will be the sum of all three cases.
Therefore, the total number of words that can be written using exactly five A's and no more than three B's (and no other letters) are 6 + 21 + 56 = 83
805 thousandths in a decimal form is 0.805.
Answer:
yellow I believe is the answer
Answer:
75in²
Step-by-step explanation:
a and b are the value of the bases. h is the height of the trapezoid
Plug in the numbers
A= 15 · 5
A= 75
