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77julia77 [94]
2 years ago
8

Hi, what is 45+b^78 divided by 67 then times 45^7?

Mathematics
1 answer:
Orlov [11]2 years ago
6 0
This is the answer for the question

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Help fast please
Lady_Fox [76]

Answer:

Acute and Obtuse..I cant see any right

Step-by-step explanation:

3 0
3 years ago
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Write the ratio of corresponding sides for the similar triangles and reduce the ratio to lowest terms.
serg [7]

Answer:

does it have a picture

Step-by-step explanation:

6 0
3 years ago
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What is 1/8 times 3/4
Serga [27]
Hi there

1/8 * 3/4

Remember: When you are multiply two fractions together all you have to do is multiply the numerator by the denominator.

Answer : 3/32

I hope that's help !
4 0
3 years ago
I arrive at a bus stop at a time that is normally distributed with mean 08:00 and SD 2 minutes. My bus arrives at the stop at an
Nimfa-mama [501]

Answer:

0.0485 = 4.85% probability that you miss the bus.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

When two normal distributions are subtracted, the mean is the subtraction of the means, while the standard deviation is the square root of the sum of the variances.

In this question:

We have to find the distribution for the difference in times between when you arrive and when the bus arrives.

You arrive at 8, so we consider the mean 0. The bus arrives at 8:05, 5 minutes later, so we consider mean 5. This means that the mean is:

\mu = 0 - 5 = -5

The standard deviation of your arrival time is of 2 minutes, while for the bus it is 3. So

\sigma = \sqrt{2^2 + 3^2} = \sqrt{13}

The bus remains at the stop for 1 minute and then leaves. What is the chance that I miss the bus?

You will miss the bus if the difference is larger than 1. So this probability is 1 subtracted by the pvalue of Z when X = 1.

Z = \frac{X - \mu}{\sigma}

Z = \frac{1 - (-5)}{\sqrt{13}}

Z = \frac{6}{\sqrt{13}}

Z = 1.66

Z = 1.66 has a pvalue of 0.9515

1 - 0.9515 = 0.0485

0.0485 = 4.85% probability that you miss the bus.

5 0
2 years ago
PLEASE HELP WILL MARK BRAINLIEST!!!!
Lyrx [107]

Answer:

y = -5x + 20

Step-by-step explanation:

Lets start with the first given values for x and y

(2,10)

Lets try out the first equation

y = 5x + 4

y = 5(2) + 4

y = 14

This equation wouldn't work because the y value is not 10 when the x value is 2

y = 5x + 20

y = 5(2) + 20

y = 30

This equation doesn't work either

y = -5x + 20

y = -5(2) + 20

y = -10 + 20

y = 10

This would be the correct equation since your y value is 10 when the x value is 2

5 0
2 years ago
Read 2 more answers
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