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2 years ago

13

The polynomial equation x^3-4x^2+10=x^2-5x-3 has complex roots 3+2i What is the other root? Use a graphing calculator and a syst

em of equations.

1 answer:

siniylev [52]2 years ago

4 0

Answer:

2

Step-by-step explanation:

1

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3 years ago

F(x)=9x^2 <br><br> g(x)= sqrt 12-x/3<br><br> (f o g)(-4)

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$f(x)=9x^2 \\ g(x)=\frac{\sqrt{12-x}}{3} \\$ So,first step is to write $(fog)(-4)) =f[g(-4)] \\$

Now we start from inner paranthesis ,we need to first find value of $g(-4) =\frac{\sqrt{12-(-4)}}{3}\\ =\frac{\sqrt{12+4}}{3}\\
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3 years ago

Answer qn in attachment

leva [86]

Answer:

$\implies \dfrac{ -4x+7}{2(x-2) }$

Step-by-step explanation:

The given expression to us is ,

$\implies \dfrac{\frac{ 3}{x-1} -4 }{ 2 -\frac{2}{x-1}}$

Now take the LCM as ( x - 1 ) and Simplify , we have ,

$\implies \dfrac{\frac{ 3 -4(x-1) }{x-1} }{ \frac{2-2(2x-1)}{x-1}}$

Simplifying further , we get ,

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Answer:

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