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exis [7]
3 years ago
14

Can someone tell me how do I finish this problem?!

Chemistry
1 answer:
Natalija [7]3 years ago
7 0
You can cross multiply, it will be easy
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Circle the correct one from given alternatives.
mash [69]

Answer:

24 is the correct anwer

this the anwer text this u no

3 0
2 years ago
Read 2 more answers
When zn(oh)2(s) was added to 1.00 l of a basic solution, 1.09×10−2 mol of the solid dissolved. what is the concentration of oh−
uysha [10]
The concentration of the basic solution is determined by:

N = (number of moles / volume of solution) 

number of moles = 1.09 x 10^-2 mol
volume of solution = 1 liter
N of basic solution = 1.09 x 10^-2 mol / 1 liter
N = 1.09 x 10^-2 mol/L

The initial concentration of Zn (OH)2 is 0; the basic solution is 1.09x10^-2 M, then the concentration of OH in the final solution is 1.09x10^-2 M



7 0
3 years ago
Read 2 more answers
At 1000 K the Kc value for the following reaction is 1.5 × 10⁶ (1) N₂O₄ (g) ⇌ 2 NO₂ (g) At 1000 K the Kc value for the following
Ahat [919]

Answer:

The value of Kc is 9.33 * 10^-17

Explanation:

Step 1: Data given

Temperature = 1000 K

N₂O₄ (g) ⇌ 2 NO₂ (g) Kc = 1.5 * 10^6

N₂ (g) + 2 O₂(g) ⇌ 2 NO₂ (g)  Kc = 1.4 * 10^-10

Step 2: Calculate Kc for  N₂ (g) + 2 O₂ ⇌ N₂O₄

N₂O₄ (g) ⇌ 2 NO₂ (g) Kc = 1.5 * 10^6

2 NO₂ (g) ⇌  N₂O₄ (g)    = 1/Kc = 1 / 1.5 * 10^6   = 6.67 *10^-7

N₂ (g) + 2 O₂(g) ⇌ 2 NO₂ (g)  Kc = 1.4 * 10^-10

Kc = Kc1 * Kc2

Kc = (6.67 *10^-7) * (1.4 * 10^-10)

Kc = 9.33 * 10 ^-17

The value of Kc is 9.33 * 10^-17

4 0
3 years ago
Solubility is usually expressed as the maximum number of grams of
Aleonysh [2.5K]

We usually expess solubility as the maximum number of grams of of a solute that will dissolve in 100 g of solvent.

For example, at 20 °C, the solubility of <em>sodium chloride</em> is <em>35.89 g/100 g water</em>.

7 0
4 years ago
What is the mass of 6.02 x 10^23 atoms of arsenic?
Anvisha [2.4K]

Answer:

Mass = 74.9 g

Explanation:

Given data:

Number of atoms of arsenic = 6.02×10²³ atoms

Mass of arsenic = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022× 10²³ is called Avogadro number.

one mole =  6.02×10²³ atoms

So number of moles of arsenic are 1 mol.

Mass of arsenic:

Mass = number of moles × molar mass

Mass = 1 mol ×  74.9 g/mol

Mass = 74.9 g

4 0
3 years ago
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