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umka2103 [35]
2 years ago
8

A gas has a volume of 250 mL at 0.29 atm. What will its volume be if the pressure is changed to 0.70

Chemistry
1 answer:
kvv77 [185]2 years ago
6 0

Answer:

yessssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss

Explanation:

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Anna35 [415]
All of them except ch2o

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2 years ago
Which statements accuratetly decribes trends found in the periodic table check all that apply
Maslowich
Peridodic table is rlly confusing
4 0
2 years ago
Consider the nitration by electrophilic aromatic substitution of salicylamide to iodosalicylamide. Reaction scheme illustrating
kvv77 [185]

<u>Answer:</u> The percent yield of the reaction is 68.68%.

<u>Explanation:</u>

To calculate the mass of salicylamide, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of salicylamide = 1.06 g/mL

Volume of salicylamide = 3.65 mL

Putting values in above equation, we get:

1.06g/mL=\frac{\text{Mass of salicylamide}}{3.65mL}\\\\\text{Mass of salicylamide}=(1.06g/mL\times 3.65mL)=3.869g

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of salicylamide = 3.869 g

Molar mass of salicylamide = 137.14 g/mol

Putting values in equation 1, we get:

\text{Moles of salicylamide}=\frac{3.869g}{137.14g/mol}=0.0295mol

The chemical equation for the conversion of salicylamide to iodo-salicylamide follows:

\text{salicylamide }+NaI+NaOCl+EtOH\rightarrow \text{iodo-salicylamide }

By Stoichiometry of the reaction:

1 mole of salicylamide produces 1 mole of iodo-salicylamide

So, 0.0295 moles of salicylamide will produce = \frac{1}{1}\times 0.0295=0.0295moles of iodo-salicylamide

Now, calculating the mass of iodo-salicylamide from equation 1, we get:

Molar mass of iodo-salicylamide = 263 g/mol

Moles of iodo-salicylamide = 0.0295 moles

Putting values in equation 1, we get:

0.0295mol=\frac{\text{Mass of iodo-salicylamide}}{263g/mol}\\\\\text{Mass of iodo-salicylamide}=(0.0295mol\times 263g/mol)=7.76g

To calculate the percentage yield of iodo-salicylamide, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of iodo-salicylamide = 5.33 g

Theoretical yield of iodo-salicylamide = 7.76 g

Putting values in above equation, we get:

\%\text{ yield of iodo-salicylamide}=\frac{5.33g}{7.76g}\times 100\\\\\% \text{yield of iodo-salicylamide}=68.68\%

Hence, the percent yield of the reaction is 68.68%.

4 0
3 years ago
Which of the following metals would be the best for the new frying pan?
Rudik [331]

Answer:

Copper

Explanation:

hope this helps!

7 0
3 years ago
How much mass do 3.4 moles of silver contain?
tensa zangetsu [6.8K]

367.2 g of silver

Explanation:

To find the mass of a substance knowing the number of moles we use the following formula:

number of mole = mass / molecular weight

In the case of silver we use the atomic weight of 108 g/mole.

mass = number of moles × molecular weight

mass of silver = 3.4 moles × 108 g/mole

mass of silver = 367.2 g

Learn more about:

moles

brainly.com/question/2293005

#learnwithBrainly

5 0
2 years ago
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