Answer: 9.9 grams
Explanation:
To calculate the moles, we use the equation:
a) moles of 
b) moles of 
According to stoichiometry :
1 mole of combine with 1 mole of
Thus 0.33 mole of will combine with =
mole of
Thus is the limiting reagent as it limits the formation of product.
As 1 mole of give = 1 mole of 
Thus 0.33 moles of give =
of
Mass of 
Thus theoretical yield (g) of produced by the reaction is 9.9 grams
Molar solubility is number of moles of the solute that can be dissolved per liter of solution before the solution becomes saturated.
The molar solubility of lead(ii) chloride with ksp value of 2.4 × 10e4 can be solve as:
Ksp = s2 = 2.4 × 10e4
s2 = 2.4 × 10e4
s = √(2.4 × 10e4)
s = 154.9 mol/L
Answer:
15g
Explanation:
The equation for the reaction is given below:
CaO + SO2 —> CaSO3
Molar Mass of CaO = 40 + 16 = 56g/mol
Molar Mass of CaSO3 = 40 + 32 + (16x3) = 40 + 32 + 48 = 120g/mol
From the equation,
56g of CaO produced 120g of CaSO3.
Therefore, 7g of CaO will produce = (7 x 120)/56 = 15g of CaSO3
Therefore, 15g of CaSO3 is produce
The correct response would be A. The slowest step that determines the speed(rate) of the overall reaction.
Answer:
d combustion because iron and oxegen need eachother
