A ratio of 0.89% w / v or 0.0089 in fraction means that
there is 0.89 weight of NaCl pero volume of solution. Therefore the mass of
NaCl is:
mass NaCl = 0.0089 * 200
<span>mass NaCl = 1.78 grams</span>
Answer:
The number of moles of the chemical constituents will be less than the actual amount.
Explanation:
In calculating empirical formula, we begin with the number of grams of each element, given in the problem.
Given that the spill will affect the mass concentration of the copper chloride solution, calculations to determine the molecular formula (using Molarity = mass conc ÷ molecular mass ) would give a lesser result, which would in turn lower the number of moles of the copper and chloride in the empirical formula calculation.
The reaction equation is:
<span>HBr + H₂SO₄ </span>→ <span>SO₂ + Br₂ + H₂O
An oxidizing agent is a substance that itself becomes reduced and oxidizes the other chemical species in the reaction mixture. A reducing agent is similar, except that it becomes oxidized and reduces the other substance.
In the reaction, the valency of bromine changes from -1 to 0, so it is oxidized, making it the reducing agent. The valency of sulfur changes from +6 to +4, so it is reduced, making it the oxidizing agent.</span>
6.4 x 10^-7 = [CO]^2[O2]/ [CO2}^2 = ( 2.0 x 10^-3)^2 ( 1.0 x 10^-3)/ [CO2]^2 =
<span>=4.0 x 10^-9 / [CO2]^2 </span>
<span>[CO]= sq.rt ( 4.0 x 10^-9)/ 6.4 x 10^-7=7.9 x 10^-2 M </span>
<span>2.6 x 10^-3 = [I]^2 / [I2] = [I]^2 / 0.95 </span>
<span>[I]= sq.rt ( 2.6 x 10^-3 x 0.95)=5.0 x 10^-2 M </span>
<span>Ksp = [Ba2+][CO32-] = ( 1.1 x 10^-4)^2=1.2 x 10^-8</span>
