⇛L = W + 5
⇛L × W = 150 sq. units
⇛W (W + 5) = 150
⇛W² + 5W = 150
⇛W² + 5W - 150 = 0
⇛[(W - 10) (W + 15)] = 0
⇛W = -10 , 15 (reject negative width)
☞ Width of rectangle is 10 units
☞ Length of rectangle is 15 units
Answer:
3.5
Step-by-step explanation:
The line AB, with A(Ax, Ay), B(Bx, By) and midpoint M(Mx, My) satisfying:
Ax + Bx = 2Mx
Ay + By = 2My
=>
2 + Bx = 2*1
5 + By = 2*2
=> Bx = 0
=> By = -1
=> B(0, -1)
Hope this helps!
:)
