All categories

3 years ago

I need help please.

Mathematics

1 answer:

jeka57 [31]3 years ago

5 0

We are trying to represent the change in position of a bird flying down 7 ft to the ground.

Often, for the y axis- up is positive and down is negative.

Change in position is displacement- how far it was from the starting point

( different from distance which is how far is traveled

ex. doubling back would have distance they traveled some distance while the displacement is 0 because they are back to where they started).

The bird is going down 7 ft from where it originally was, which can be represented by

Bird's displacement = -7 ft

You might be interested in

A city has an elevation of –752 feet. Which statement describes the city’s elevation?

tankabanditka [31]

Answer:

752 below sea level

just took it.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Part 2. Laws of sines. Please show work. Round answer to the nearest tenth.

Bingel [31]

Answer:

5) 30.0m

6) 34.0mi

7) 11.0ft

8) 17.0 km

(all rounded off to the nearest tenth)

Step-by-step explanation:

Please see attached pictures for the full solution.

6 0

2 years ago

Please I need help!!!

Natalija [7]

Answer:

Step-by-step explanation:

-14 + x = 44

x = 44 + 14

x = 58

3 0

2 years ago

Carrie and brent leave home at the same time. carrie drives due east at a rate of 30 mph, while brent drives due south at a rate

Helga [31]

<h3>They are 268 miles far apart after 4 hours</h3>

<h3>Further explanation</h3>

Acceleration is rate of change of velocity.

$\large {\boxed {a = \frac{v - u}{t} } }$

$\large {\boxed {d = \frac{v + u}{2}~t } }$

<em>a = acceleration ( m/s² )</em>

<em>v = final velocity ( m/s )</em>

<em>u = initial velocity ( m/s )</em>

<em>t = time taken ( s )</em>

<em>d = distance ( m )</em>

Let us now tackle the problem !

<u>Given :</u>

v₁ = 30 mph due east

v₂ = 60 mph due south

t = 4 hours

<u>Unknown :</u>

displacement = d = ?

<u>Solution :</u>

$d_1 = v_1 \times t$

$d_1 = 30 ~ mph \times 4 ~ h$

$d_1 = \boxed {120 ~ miles}$

$d_2 = v_2 \times t$

$d_2 = 60 ~ mph \times 4 ~ h$

$d_2 = \boxed {240 ~ miles}$

$d^2 = (d_1)^2 + (d_2)^2$

$d^2 = 120^2 + 240^2$

$d^2 = 72000$

$d = \sqrt{72000}$

$d = 120\sqrt{5} ~ miles$

$d \approx \boxed {268 ~ miles}$

<h2>Conclusion :</h2><h3>They are 268 miles far apart after 4 hours</h3>

<h3>Learn more</h3>

Velocity of Runner : brainly.com/question/3813437
Kinetic Energy : brainly.com/question/692781
Acceleration : brainly.com/question/2283922
The Speed of Car : brainly.com/question/568302

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate

6 0

3 years ago

Read 2 more answers

Use two rectangles of equal width to estimate the area between the graph of f(x) = x + cos(πx) and the x-axis on the interval [2

MrRissso [65]

We find the base of the rectangles by taking the difference between the interval endpoints, and dividing by 2.
Base of rectangle = (6 - 2) / 2
= 2

The area of the first rectangle:

(4 - 2)f(4) = 2[4 + cos(4π)]

The area the second triangle:

(6 - 4)f(6) = 2[6 + cos(6π)]

Now just compute the two areas and combined them. That will give you the estimated under the curve.

To evaluate the midpoint of each rectangle, we take the midpoint of the base lengths of each rectangle. This midpoint is the x value. Then evaluate the function at that x value.

The midpoint of the first rectangle is x=3. Evaluate f(3).
The midpoint of the second rectangle is x=5. Evaluate f(5).

7 0

3 years ago