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sertanlavr [38]
3 years ago
8

Let n be a whole number, and consider the statements below. p: n is a multiple of two. q: n is an even number. Which of the foll

owing is equivalent to ~q → ~p? A. ~q → ~p B. q → p C. p → q D. ~p →~
Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
5 0

Answer:

C. p -> q

Step-by-step explanation:

Just did this on Edge2020. Hope this helps :)

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Is this positive, negative, none or you cannot tell. Will mark CORRECT brainliest
pshichka [43]

Answer:

Positive correlation if right. Atleast consider brainlist:)

Step-by-step explanation:

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3 years ago
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Monday<br> What time is 5 3/4 hours after<br> 11:32 pm?
Marina86 [1]

bearing in mind that the an hour has 15 + 15 + 15 + 15 = 60 minutes, so 15 minutes in 1/4 of an hour, thus 45 minutes is 3/4 of an hour.

now, from 11PM, if we add the 5 hours first, we'll be at 4AM, pass midnight of course.

now let's add the minutes, 32 and then 45, that gives us 77 minutes.

so the time will be 4AM plus 77 minutes, since 60 minutes is 1 hr, so 4AM plus 1 hr and 17 minutes, that'd be 5:17AM.

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3 years ago
Please answer this multiple choice question CORRECTLY for 30 points and brainliest!!
JulijaS [17]

Solve the inequality for x:

5x - 3 ≤ 7x +7

Subtract 7x from each side:

-2x -3 ≤ 7

Add 3 to each side:

-2x ≤ 10

Divide both sides by -2, also when dividing  both sides of an inequality you flip the direction of the inequality sign:

x ≥ -5

The dot will be on -5, because the inequality includes equal to, the dot is solid and is greater than, the arrow will point to the right.

The correct answer is D.

4 0
4 years ago
Simplify the expression 5^3 x 5^-5
kotykmax [81]

Answer:

\frac{1}{5^2} --- 1 over 5 squared

Step-by-step explanation:

When multiplying terms with a common base, you just add the exponents:

x^a\times x^b=x^{a+ b}

That's true even when you don't have any exponents.

5\times5=5^1\times5^1=5^{1+1}=5^2=25

\rightarrow5^3\times5^{-5}\\\rightarrow5^{3-5}\\\rightarrow5^{-2}

A negative exponent isn't fully simplified, so there's another rule to use:

x^{-y}=\frac{1}{x^y}

That is '1 over x to the y' if it's too small to read.

\rightarrow5^{-2}=\frac{1}{5^2}

4 0
2 years ago
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Factor these expressions into an equivalent form.
Marrrta [24]
(c+8)(c-8)

3(2y+5)(2y-5)

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7 0
3 years ago
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