The best thing to do is to find what 1% is, and you can do this by dividing 150 by 100.
150/100= 1.5
As you're looking for 6.5%, you've got to multiply 1.5 by 6.5
1.5*6.5= 9.75
You've then got to add 9.75 and 150 together
150+9.75= $159.75
Therefore, after the sales tax, the cost of the necklace is $159.75
Hope this helps :)
w is the width and it is the independent variable. You can pick any positive whole number you want (within reason of course; you can't go to infinity or go beyond some set boundary). Whatever you picked for w, the expression 2w-5 will be dependent on it. So the length is dependent on the width.
For instance, if the width is w = 10 feet, then 2w-5 = 2*10-5 = 20-5 = 15 feet is the length. The choice of 10 feet for the width directly affects the length being 15 feet.
Answer:
Step-by-step explanation:
We have been given the absolute value parent function f(x) = |x| and this function is vertically compressed by a factor 3.
If we multiply the function with a constant (say a) then the parent function will get stretch/compressed vertically.
We have below conditions for vertical stretch and compression.
a > 1 => vertically stretch
0 < a < 1 => vertically compression
Hence, in order to vertical compression by a factor 3, we have to multiply the whole function by 1/3
Therefore, the equation for new function is
pls mark as brainliest
First, you have to find<span> the axis of symmetry and vertex. Next, make a function to model a linear relationship between the two quantities. Finally, find the rate of change and </span>initial value<span> of the function from a description of a relationship or from 2 (x , y) </span>values<span>, including reading these from graph or a table.</span>
-4x-2y = 16
2y = -4x-16
Get one variable alone on both equations
-4x - 16 = 2y
-4x - 16 = 2y
You'll realize that they're the same equation.
Use substitution
-4x-16 = -4x-16
0 = 0
x = all solutions
Use x = all solutions in an earlier equation to find y
-4x - 16 = 2y
SInce x can be all solutions y is also all solutions
y = all solutions
