Answer:
<h2>The answer is 14.29 %</h2>
Explanation:
The percentage error of a certain measurement can be found by using the formula

From the question
actual density = 0.70 g/mL
error = 0.8 - 0.7 = 0.1
So we have

We have the final answer as
<h3>14.29 %</h3>
Hope this helps you