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yaroslaw [1]
3 years ago
12

This is any sunstance with constant composition

Chemistry
1 answer:
FromTheMoon [43]3 years ago
5 0

Answer:

A pure substance has a constant composition and cannot be separated into simpler substances by physical means. There are two types of pure substances: elements and compounds. ... The ratio of the elements in a compound are always constant. (Water is always 11 % Hydrogen and 89 % oxygen).

Explanation:

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AmbienTM is a sedative used in the treatment of insomnia. It was discovered in 1982 and brought to market in 1992 (it takes a lo
mixer [17]

Answer:

sp3 - 1,2,13,16,18,19

sp2- 3,4,5,6,7,8,9,10,11,12,14,15,17

sp- 0

Explanation:

Hybridization is the idea that atomic orbitals fuse to form newly hybridized orbitals, which in turn, influences molecular geometry and bonding properties (Chemlibretexts).

Carbon atoms that are singly bonded are sp3 hybridized, carbon atoms that are doubly bonded are sp2 hybridized while carbon atoms that are triply bonded are sp hybridized.

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The hybridization state of each atom in the compound has been shown in the answer section.

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2 years ago
What sport was used to demonstrate Newton's 3 Laws?
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2 years ago
Which factors are most likely to limit population growth in cloud forests?
antoniya [11.8K]

Answer:

Option (4)

Explanation:

The cloud forests are located at high elevated areas in the tropical and subtropical regions. They are characterized by the presence of clouds that maintains a relatively cold environment, favoring the existence of various type of plant and animal species. The temperature is comparatively low, rich in moisture content and the amount of sunlight also is low in this region. The change in these factors can cause a decrease in the population growth in these cloud forests.

Thus, low moisture content in the atmosphere and excessive amount of sunlight in this type of forest can lead to the reduction in its population.

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5 0
3 years ago
Consider 4.00 L of a gas at 365 mmHg and 20. ∘C . If the container is compressed to 2.80 L and the temperature is increased to 3
stealth61 [152]

This is an exercise in<u> the General Combined Gas Law</u>.

To start solving this exercise, we obtain the following data:

<h3>Data:</h3>
  • V₁ = 4.00 l
  • P₁ = 365 mmHg
  • T₁ = 20 °C + 273 = 293 K
  • V₂ = 2,80 l
  • T₂ = 30 °C + 273 = 303 K
  • P₂ = ¿?

We apply the following formula:

  • P₁V₁T₂=P₂V₂T₁     ⇒  General formula

Where:

  • P₁=Initial pressure
  • V₁=Initial volume
  • T₂=end temperature
  • P₂=end pressure
  • T₂=end temperature
  • V₁=Initial temperature

We clear for final pressure (P2)

\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{P_{1}V_{1}T_{2}}{V_{2}T_{1}} \ \ \to \ \ \ Formula \end{gathered}$}

We substitute our data into the formula:

\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{(365 \ mmHg)(4.00 \not{l})(303 \not{K})}{(2.80 \not{l})(293\not{K})}  \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{442380 \ mmHg}{ 820.4 }  \end{gathered}$}

\boxed{\large\displaystyle\text{$\begin{gathered}\sf P_{2}=539.224 \ mmHg \end{gathered}$}}

Answer: The new canister pressure is 539.224 mmHg.

<h2>{ Pisces04 }</h2>
6 0
1 year ago
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