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Elanso [62]
2 years ago
9

Thomson found that the cathode rays were actually streams of with the following properties: ________

Chemistry
2 answers:
kiruha [24]2 years ago
3 0

The cathode rays are also known as electrons. They are a stream of negatively charged particles.

<h3>What are cathode rays?</h3>

The term cathode rays were used by JJ Thompson to describe a stream of rays that emanate from the cathode in a cathode ray tube. These rays correspond to what we know today as electrons.

The cathode rays;

  • Travelled in straight lines
  • Depended on the nature of gas in the tube
  • Were deflected by electric and magnetic fields
  • Produced mechanical motion in objects on their path.

Learn more about cathode rays: brainly.com/question/1825212

ddd [48]2 years ago
3 0

Electron beams such as cathode rays travel in a straight line.

<h3>What are Cathode rays?</h3>

Cathode rays are electrons that are observed in vacuum tubes, is streams of electrons are emitted by the negative electrode.

  • Cathode rays travel in straight lines and usually cast sharp shadows.
  • Cathode rays are negatively charged electrode
  • Cathode rays are usually deflected by an electric and magnetic field.

Therefore, cathode rays traveled in straight lines, they were the composition of the material from which they originated, and they carried a negative electrical charge.

Learn more on cathode rays here,

brainly.com/question/4441361

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Due to the small and highly electronegative nature of fluorine, the oxyacids of the this element are much less common and less s
Molodets [167]

Answer:

HOFO = (0, 0, +1, -1)

Explanation:

The formal charge (FC) can be calculated using the following equation:

FC = V - N - \frac{1}{2}B

<u>Where:</u>

V: are the valence electrons

N: are the nonbonding electrons

B: are the bonding electrons

The arrange of the atoms in the oxyacid is:

H - O₁ - F - O₂

Hence, the formal charge (FC) on each of the atoms is:

H: FC = 1 - 0 - 1/2*(2) = 0            

O₁: FC = 6 - 4 - 1/2*(4) = 0        

F: FC = 7 - 4 - 1/2*(4) = +1

O₂: FC =  6 - 6 - 1/2*(2) = -1

We can see that the negative charge is in the oxygen instead of the most electronegative element, which is the F. This oxyacid is atypical.  

I hope it helps you!

3 0
3 years ago
Chemical weathering processes do not alter the chemical structure of minerals in rocks. *
Anna007 [38]
I THINK that that is true. It's just weathering the rock down not change composition. Lemme know if you get it right please! (:
4 0
3 years ago
Which element gains two electrons to fill its outermost energy level?
laiz [17]
O magnesium Mg is the answer
4 0
2 years ago
The chart below lists data on four different projects designed to restore a wetlands habitat destroyed by human activity and a r
snow_lady [41]

Answer:

Project 3.

Explanation:

Project 3's anticipated cost is 12 to 17 million dollars. It is a <em>lower </em>anticipated cost than Project 2 and Project 4, but <em>higher</em> than Project 1 by one million dollars at maximum cost anticipation. Additionally, the percentage of wildlife to benefit is 70-80%, which is <em>second</em> to the most wildlife to benefit which is Project 4 at 75-80%.

And finally, for community support for Project 3 - the chart lists it as high. This outclasses Project 2 and Project 4, but balances with Project 1. However, Project 1 costs 13 to 16 million dollars and <em>only</em> benefits 15-25% of wildlife.

5 0
2 years ago
A common fuel additive that is composed of C, H, and O enhanced the performance of gasoline began being phased out in 1999 becau
spayn [35]

Answer:

C₅ H₁₂ O

Explanation:

44 g of CO₂ contains 12 g of C

30.2 g of CO₂ will contain 12 x 30.2 / 44 = 8.236 g of C .

18 g of H₂O contains 2 g of hydrogen

14.8 g of H₂0 will contain 1.644 g of  H .

total compound = 12.1 out of which 8.236 g is C and 1.644 g is H , rest will be O

gram of O = 2.22

moles of C, O, H in the given compound =  8.236 / 12 , 2.22 / 16 , 1.644 / 1

= .6863 , .13875 , 1.644

ratio of their moles = 4.946 : 1 : 11.84

rounding off to digits

ratio = 5 : 1 : 12

empirical formula = C₅ H₁₂ O

6 0
3 years ago
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