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tankabanditka [31]
3 years ago
8

8. What group numbers are the transition elements in?

Chemistry
1 answer:
Anna007 [38]3 years ago
3 0
The 38 elements in groups 3 through 12 of the periodic table are called "transition metals". As with all metals, the transition elements are both ductile and malleable, and conduct electricity and heat. The interesting thing about transition metals is that their valence electrons, or the electrons they use to combine with other elements, are present in more than one shell. This is the reason why they often exhibit several common oxidation states. There are three noteworthy elements in the transition metals family. These elements are iron, cobalt, and nickel, and they are the only elements known to produce a magnetic field I HOPE THIS HELP:)
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Consider the following set of ions: Al3+; Li+, Rb+, [(C4H9)4N+].
krok68 [10]

Hey there!:

a) Cations which are lowest size generally forms adopts more number of water molecules around it. Such kind of Cations forms largest hydrated ions. Among given cations, Li+ is smallest one and (C4H9)4N+ is largest one. So, Li+ ion forms largest hydrated ion.

b) Organic ligands or alkyl chains contained Cations are hydrophobic in nature due to its low polar nature. Among given (C₄H₉)4N⁺ cation is hydrophobic in nature.

c) Size of cation inversely proportional to the hydrated sphere or number of water molecules attached. So, in the given Cations  (C₄H₉)4N⁺ is largest cation which attaches fewest water molecules.

d) Charge on the cation makes it more electrostatic maker. But size is inversily proportional to electrostatic property. (C₄H₉)4N⁺ is electrostatic structure breaker.

e) Al⁺³ has highest charge. So it is most electrostatic structure maker.

Hope this helps!

3 0
3 years ago
A 2-kg bowling
Volgvan
So for the first one It's 784.56 J (GPE)

For the second one it's KE is equal to 100 J. If you can give me a few more minutes I'll try to get the GPE
6 0
4 years ago
Read 2 more answers
Ecosystems do not have similar climates and every plant is different True or false
Soloha48 [4]
This is false. Some plants are the same or at least very similar
4 0
2 years ago
A hypothetical element has an atomic weight of 48.68 amu. It consists of three isotopes having masses of 47.00 amu, 48.00 amu, a
Morgarella [4.7K]

Answer : The percent abundance of the heaviest isotope is, 78 %

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

As we are given that,

Average atomic mass = 48.68 amu

Mass of heaviest-weight isotope = 49.00 amu

Let the percentage abundance of heaviest-weight isotope = x %

Fractional abundance of heaviest-weight isotope = \frac{x}{100}

Mass of lightest-weight isotope = 47.00 amu

Percentage abundance of lightest-weight isotope = 10 %

Fractional abundance of lightest-weight isotope = \frac{10}{100}

Mass of middle-weight isotope = 48.00 amu

Percentage abundance of middle-weight isotope = [100 - (x + 10)] %  = (90 - x) %

Fractional abundance of middle-weight isotope = \frac{(90-x)}{100}

Now put all the given values in above formula, we get:

48.68=[(47.0\times \frac{10}{100})+(48.0\times \frac{(90-x)}{100})+(49.0\times \frac{x}{100})]

x=78\%

Therefore, the percent abundance of the heaviest isotope is, 78 %

5 0
3 years ago
Read 2 more answers
Explain how you would determine the amount of g in 1.7 mol of Al(OH)2 and give your answer.
krok68 [10]

Answer:

103.7 grams

Explanation:

Al(OH)_{2}

Al: 1 * 26.98 = 26.98

O: 2 * 16.00 = 32.00

H: 2 * 1.01 = 2.02

26.98 + 32.00 + 2.02 = 61.00

\frac{1.7mol}{1} * \frac{61.00g}{1mol} = 103.7 grams of Al(OH)_{2}

6 0
3 years ago
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