The ka of acetic acid ch3co2h is 1.8 x10-5. what is the ph

1 answer:

6 0

You must know the concentration of the acetic acid. Suppose the concentration is 0.1 M. The solution is as follows:

CH₃COOH → CH₃COO⁻ + H⁺
I 0.1 0 0
C -x +x +x
E 0.1 - x x x

Ka = (x)(x)/(0.1 - x)
1.8×10⁻⁵ = x²/(0.1 - x)
Solving for x,
x = 1.333×10⁻³ = H⁺

pH = -log[H⁺] = -log(1.333×10⁻³)
pH = 2.88

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