Identify four techniques that take advantage of different physical

Which of the following is an oxidation-reduction reaction? a. HCl(aq) + LiOH(aq) → LiCl(aq) + H2O(l) b. Pb(C2H3O2)2(aq) + 2 NaCl

saw5 [17]

Answer: Option (d) is the correct answer.

Explanation:

A reaction in which there occurs change in oxidation state of reacting species is known as an oxidation-reduction reaction.

(a) $HCl(aq) + LiOH(aq) \rightarrow LiCl(aq) + H_{2}O(l)$

Will be written as:

$H^{+} + Cl^{-} + Li^{+} + OH^{-} \rightarrow Li^{+} + Cl^{-} + H^{+} + OH^{-}$

In this reaction, there occurs no change in oxidation state of reacting species. Hence, it is not an oxidation-reduction reaction.

(b) $Pb(C_{2}H_{3}O_{2})_{2}(aq) + 2NaCl(aq) \rightarrow PbCl_{2}(s) + 2 NaC_{2}H_{3}O_{2}(aq)$

Will be written as:

$Pb^{2+} + 2C_{2}H_{3}OO^{-} + 2Na^{+} + 2Cl^{-} \rightarrow Pb^{2+} + 2Cl^{-} + 2Na^{+} + 2C2H3OO^{-}$

Similarly here, there occurs no change in oxidation state of reacting species. Hence, it is not an oxidation-reduction reaction.

(c) $NaI(aq) + AgNO_{3}(aq) \rightarrow AgI(s) + NaNO_{3}(aq)$

Will be written as:

$Na^{+} + I^{-} + Ag^{2+} + NO^{2-}_{3} \rightarrow AgI(s) + Na^{+} + NO^{2-}_{3}(aq)$

Here, also there occurs no change in oxidation state of reacting species. Hence, it is not an oxidation-reduction reaction.

(d) $Mg(s) + 2 HCl(aq) \rightarrow MgCl_{2}(aq) + H_{2}(g)$

So, here there occurs change in oxidation state of Mg from 0 to +2 and oxidation state of H changes from +1 to 0. Hence, it is an oxidation-reduction reaction.

Thus, we can conclude that $Mg(s) + 2 HCl(aq) \rightarrow MgCl_{2}(aq) + H_{2}(g)$ is an oxidation-reduction reaction.

7 0

3 years ago

In which states of matter can an object change both volume and shape

Masja [62]

Answer:

Liquid

Explanation: Obviously

4 0

3 years ago

Read 2 more answers

Lorek lives near the North Pole. The snow in his backyard adds water to the atomosphere through______.

Elis [28]

Hello :))

Your question was:Lorek lives near the North Pole. The snow in his backyard adds water to the atomosphere through______.
The answer is: Sublimation

Hope this helps!
Good day! :D

3 0

3 years ago

What is the oxidation state of cr in CrPO4 and Cr3(PO4)2?

soldi70 [24.7K]

Answer:

Explanation:

Oxidation state of Cr in CrPO₄

As a general rule, the algebraic sum of all the oxidation numbers of all atoms in a neutral compound is zero.

The compound above is in its neutral state and we sum all the oxidation numbers and equate to zero:

The oxidation number of P is -2

O is -2

Let the oxidation number of Cr be x:

x + (-2) + 4(-2) = 0

x -2-8 = 0

x -10 = 0

x = +10

For Cr in Cr₃(PO₄)₂

Using the same rule:

2(x) + 2[-2 + 4(-2)] = 0

2x + 2(-2-8) = 0

2x -20 = 0

x = +10

6 0

3 years ago

Read 2 more answers

Using the molecular weight (258 g/mol) determine the amount of mmol of (3S)-2,2,- dibromo-3,4-dimethylpentane required.

Varvara68 [4.7K]

The question is incomplete, the complete question is;

With all of this data in hand, we can now set up our reaction. To begin we are going to use 0.7 g of (35)-2.2-dibromo-3,4-dimethylpentane. Question #7: Using the molecular weight (258 g/mol) determine the amount of mmol of (3S)-2,2,- dibromo-3,4-dimethylpentane required. Round to the tenths place

Answer:

2.70 mmols

Explanation:

Given that;

Mass of (3S)-2,2,- dibromo-3,4-dimethylpentane = 0.7 g

Molar mass of (3S)-2,2,- dibromo-3,4-dimethylpentane = 258 g/mol

From,

Number of moles = mass/molar mass

Number of moles of (3S)-2,2,- dibromo-3,4-dimethylpentane = 0.7g/258 g/mol = 2.7 ×10^-3 moles

Therefore;

Number of moles of (3S)-2,2,- dibromo-3,4-dimethylpentane = 2.70 mmols

8 0

4 years ago