Salt is usually formed during neutralization reactions,
that is the reaction of an acid and a base. This is illustrated as follows:
<span>HX + YOH --> XY
+ H2O</span>
where XY is the salt
From the given choices, the only pair of acid and base is:
<span>Vinegar and antacids</span>
Answer : The correct expression is, (150 × 3 × 31.998) ÷ (232.29 × 1) grams
Explanation :
First we have to calculate the moles of 

Now we have to calculate the moles of 
The balanced chemical reaction is,

From the balanced chemical reaction we conclude that,
As, 1 mole of
react to give 3 mole of 
So,
moles of
react to give
moles of 
Now we have to calculate the mass of 


Therefore, the correct expression for the mass of oxygen gas formed is, (150 × 3 × 31.998) ÷ (232.29 × 1) grams
Answer:
The reaction quotient (Q) before the reaction is 0.32
Explanation:
Being the reaction:
aA + bB ⇔ cC + dD
![Q=\frac{[C]^{c} *[D]^{d} }{[A]^{a}*[B]^{b} }](https://tex.z-dn.net/?f=Q%3D%5Cfrac%7B%5BC%5D%5E%7Bc%7D%20%2A%5BD%5D%5E%7Bd%7D%20%7D%7B%5BA%5D%5E%7Ba%7D%2A%5BB%5D%5E%7Bb%7D%20%20%7D)
where Q is the so-called reaction quotient and the concentrations expressed in it are not those of the equilibrium but those of the different reagents and products at a certain instant of the reaction.
The concentration will be calculated by:

You know the reaction:
PCl₅ (g) ⇌ PCl₃(g) + Cl₂(g).
So:
![Q=\frac{[PCl_{3} ] *[Cl_{2} ] }{[PCl_{5} ]}](https://tex.z-dn.net/?f=Q%3D%5Cfrac%7B%5BPCl_%7B3%7D%20%5D%20%2A%5BCl_%7B2%7D%20%5D%20%7D%7B%5BPCl_%7B5%7D%20%5D%7D)
The concentrations are:
- [PCl₃]=

- [Cl₂]=

- [PCl₅]=

Replacing:

Solving:
Q= 0.32
<u><em>The reaction quotient (Q) before the reaction is 0.32</em></u>
Answer:
Acids have a pH less than 7. Acids contain lots of hydrogen ions
Alkalis have a pH greater than 7. Alkalis contain lots of hydroxide ions
<u><em></em></u>
<u><em>Please mark as brainliest if answer is right </em></u>
Have a great day, be safe and healthy
Thank u
XD