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4 years ago

Match each alkane names and structures.

Chemistry

1 answer:

Scilla [17]4 years ago

6 0

First structure is CH₃-CH₃. It is an alkane with two carbon atoms hence it is called ethane.

Second structure is CH₃-CH₂-CH₂-CH₃. It is an alkane with four carbon atoms hence it is called butane.

Third structure is CH₄. It is an alkane with one carbon atom hence it is called methane.

Fourth structure is CH₃-CH₂-CH₃. It is an alkane with three carbon atoms hence it is called propane.

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Answer:

The mass of calcium sulfate that will precipitate is 6.14 grams

Explanation:

<u>Step 1:</u> Data given

500.0 mL of 0.10 M Ca^2+ is mixed with 500.0 mL of 0.10 M SO4^2−

Ksp for CaSO4 is 2.40*10^−5

<u>Step 2:</u> Calculate moles of Ca^2+

Moles of Ca^2+ = Molarity Ca^2+ * volume

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<u>Step 3: </u>Calculate moles of SO4^2-

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Moles SO4^2- = 0.05 moles

<u>Step 4: </u>Calculate total volume

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<u>Step 5: </u> Calculate Q

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Qsp = (0.050)(0.050 )=0.0025 >> Ksp

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<u> Step 6:</u> Calculate molar solubility

Ksp = 2.40 * 10^-5 = [Ca2+][SO42-] =(x)(x)

2.40 * 10^-5 = x²

x = √(2.40 * 10^-5)

x = 0.0049 M = Molar solubility

<u> Step 7:</u> Calculate total CaSO4 dissolved

total CaSO4 dissolved = 0.0049 M * 1 L * 136.14 mol/L = 0.667 g

<u>Step 8:</u> Calculate initial mass of CaSO4

Since initial moles CaSo4 = 0.050

Initial mass of CaSO4 = 0.050 * 136.14 g/mol

Initial mass of CaSO4 = 6.807 grams

<u>Step 9:</u> Calculate mass precipitate

6.807 - 0.667 = 6.14 grams

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