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Kitty [74]
3 years ago
10

A number line is numbered in tenths Describe where you would plot √87.35

Mathematics
1 answer:
sleet_krkn [62]3 years ago
7 0

Answer:

Plot at 9.3

Step-by-step explanation:

Take the square root of 87.35

sqrt(87.35)

9.346122191

Rounding to the nearest tenth

9.3

Plot at 9.3

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In Jacks class, 75% of the students are girls. there are 18 girls in the class. what is the total number if students in the clas
Andre45 [30]
18 = .75x
/.75   /.75 (divide both sides by .75 to isolate x)

24 = x

24 total students

Hope this helps!
6 0
3 years ago
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∠A and \angle B∠B are supplementary angles. If m\angle A=(2x-16)^{\circ}∠A=(2x−16) ∘ and m\angle B=(5x+28)^{\circ}∠B=(5x+28) ∘ ,
Otrada [13]

Answer:

The measure of angle A is 32

Step-by-step explanation:

A+B=180

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7x+12=180

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4 years ago
The cost to take a taxi includes a flat rate, plus a charge for the number of miles the taxi travels.
Alenkasestr [34]

Answer:

412$

Step-by-step explanation:

7 0
3 years ago
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Please give an explanation on how you got this answerI'm not sure if it's too late or what, but I can't get it.
Alona [7]
Step 1: multiple the second equation by 2 so that you get -1/4 for the coefficient of y, the same as in equation 1
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8 0
3 years ago
Of those women who are diagnosed to have early-stage breast cancer, one-third eventually die of the disease. Suppose a screening
Finger [1]

Answer:

A) Alternative hypothesis; Ha: p_o > ⅔

B) Null hypothesis;

H0: p_o = ⅔

C) There is sufficient evidence to support the claim that the community screening programme was effective

D) p-value = 0

Its less than the significance value and so we will reject the null hypothesis and conclude that the community screening programme was effective

Step-by-step explanation:

A) We are told that ⅓ of those diagnosed eventually die of the disease. Thus, ⅔ is the fraction that will survive the disease.

Thus, the null hypothesis is;

H0: p_o = ⅔

We are told that a screening programme was started to increase the survival rate. Thus,the alternative hypothesis is;

Ha: p_o > ⅔

B) null hypothesis is;

H0: p_o = ⅔

C) 164 out of the 200 women selected survived the disease.

Thus sample proportion is;

p^ = 164/200

p^ = 0.82

For the z-score value, we will use the formula;

z = (p^ - p_o)/√((p_o(1 - p_o)/n)

Now, p_o = ⅔ = 0.67

Thus;

z = (0.82 - 0.67)/√((0.67(1 - 0.67)/200)

z = 4.51

From online p-value from z-score calculator, we have p-value ≈ 0

This is less than the significant level of 0.05 and therefore we will reject the null hypothesis and conclude that the community screening program was effective.

D) p-value ≈ 0

Reject the null hypothesis

4 0
2 years ago
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