The answer would be b. THis is becuse the second choice has less than or equal to and just less than signs. This is what is shown on the graph. The open circles are the less than sides, and the closed circles mean less than or equal to. Hope this helps.
Answer:
center = origin (0,0)
radius = 3
to graph it, draw a circle that goes through the points (3,0), (0,3), (-3,0), (0,-3)
Step-by-step explanation:
Answer:
See below.
Step-by-step explanation:
I will assume that 3n is the last term.
First let n = k, then:
Sum ( k terms) = 7k^2 + 3k
Now, the sum of k+1 terms = 7k^2 + 3k + (k+1) th term
= 7k^2 + 3k + 14(k + 1) - 4
= 7k^2 + 17k + 10
Now 7(k + 1)^2 = 7k^2 +14 k + 7 so
7k^2 + 17k + 10
= 7(k + 1)^2 + 3k + 3
= 7(k + 1)^2 + 3(k + 1)
Which is the formula for the Sum of k terms with the k replaced by k + 1.
Therefore we can say if the sum formula is true for k terms then it is also true for (k + 1) terms.
But the formula is true for 1 term because 7(1)^2 + 3(1) = 10 .
So it must also be true for all subsequent( 2,3 etc) terms.
This completes the proof.
Answer:
Length l = 15 - 2x = 15 - 2(1.5) = 12.00 in
Breadth b = 7 - 2x = 7 - 2(1.5) = 4.00 in
Height h = x = 1.50 in
Step-by-step explanation:
The volume of a box can be written as;
V = l×b×h
Where;
Length = l
Breadth = b
Height = h
Let x represent the length of the cube cut out of the four edges.
Using the attached image;
Length l = 15 - 2x
Breadth b = 7 - 2x
Height h = x
Substituting the values to the volume equation;
V = (15-2x)(7-2x)(x)
V = 105x - 30x^2 - 14x^2 + 4x^3
V = 105x - 44x^2 + 4x^3
At Maximum volume, V' = dV/dx = 0
V' = 105 - 88x + 12x^2 = 0
Solving the quadratic equation, we have;
x = 5.83 or x = 1.50
x cannot be 5.83 since 2x > 7 (greater than the breadth of cardboard)
Therefore ;
Length l = 15 - 2x = 15 - 2(1.5) = 12.00 in
Breadth b = 7 - 2x = 7 - 2(1.5) = 4.00 in
Height h = x = 1.50 in