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Gnoma [55]
3 years ago
12

If 1 +2 is 21 and 2 + 3 is 36 what is 4 + 5

Mathematics
2 answers:
lara31 [8.8K]3 years ago
7 0
4+5 would be 9 because you add 4 and 5
trasher [3.6K]3 years ago
3 0
<h2>Answer:</h2>

4+5=65

<h2>Step-by-step explanation: </h2><h3><u>First term: </u></h3>

Step 1: We need to add the numbers.

\Rightarrow 1+2=3

Step 2: We need to multiply the obtained number with ‘7’.

\Rightarrow 1+2=3 \times 7=21

Step 3: We need to add the obtained number with ‘0’.

\therefore 1+2=3 \times 7=21+0=21

<h3><u>Second term: </u></h3>

Step 1: We need to add the numbers.

\Rightarrow 2+3=5

Step 2: We need to multiply the obtained number with ‘7’.

\Rightarrow 2+3=5 \times 7=35

Step 3: We need to add the obtained number with ‘1’.

\therefore 2+3=5 \times 7=35+1=36

<h3><u>Thus, third term will: </u></h3>

Step 1: We need to add the numbers.

\Rightarrow 4+5=9

Step 2: We need to multiply the obtained number with ‘7’.

\Rightarrow 4+5=9 \times 7=63

Step 3: We need to add the obtained number with ‘2’.

\therefore 4+5=9 \times 7=63+2=65

Since, the options are not given, we can take the liberty to apply any method in this problem.

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Answer:

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Step-by-step explanation:

Plot points  A(5,2), B(-1,4), C(-2,1) and D(4,-1) on the coordinate plane. Find lengths of all sides as distances between two points:

AB=\sqrt{(-1-5)^2+(4-2)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=2\sqrt{10}\ units\\ \\BC=\sqrt{(-2-(-1))^2+(1-4)^2}=\sqrt{1^2+3^2}=\sqrt{1+9}=\sqrt{10}\ units\\ \\CD=\sqrt{(4-(-2))^2+(-1-1)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=2\sqrt{10}\ units\\ \\DA=\sqrt{(5-4)^2+(2-(-1))^2}=\sqrt{1^2+3^2}=\sqrt{1+9}=\sqrt{10}\ units

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AB+BC+CD+DA=2\sqrt{10}+\sqrt{10}+2\sqrt{10}+\sqrt{10}=6\sqrt{10}\approx 18.97\ units\approx 19\ units

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3 years ago
Please explain how to do this im confused
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