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umka21 [38]
3 years ago
7

What is 5x^2y^-3 simplified?

Mathematics
2 answers:
xxTIMURxx [149]3 years ago
6 0

Answer:

(5x^2)/(y^3)

Step-by-step explanation:

olya-2409 [2.1K]3 years ago
4 0

Answer:

(5x^2)/(y^3)

Step-by-step explanation:

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When Sean stands on a box, he is 10 feet tall. If the box is 4 feet tall, write and solve an addition equation to find Sean's he
Phoenix [80]
X+4=10
x=10-4=6
----------------
5 0
3 years ago
Two capacitors, a 20 mF and a 30 mF, are connected in parallel to a 400 Hz source. The total capacitive reactance is _____.
muminat

<u>Answer</u>-

<em>The total capacitive reactance of the circuit is </em><em>7.96 Ω.</em>

<u>Solution-</u>

Two capacitors, a 20 mF and a 30 mF, are connected in parallel to a 400 Hz source.

The effective/equivalent capacitance of the circuit is,

C=20+30=50\ mF

As, when capacitors are connected together in parallel, the equivalent capacitance in the circuit is equal to the sum of capacitance of all the individual capacitor.

We know that,

X_c=\dfrac{1}{2\pi fC}

Where,

X_c = Capacitive Reactance (in Ω)

f = frequency (in Hz)

C = Capacitance (in F)

Here given,

X_c = ??

f = 400 Hz

C = 50 mF = 50\times 10^{-6} F

Putting the values in the formula,

X_c=\dfrac{1}{2\pi \times 400\times 50\times 10^{-6}}

X_c=\dfrac{10^{6}}{40000\pi}

X_c=7.96\ \Omega

Therefore, the total capacitive reactance of the circuit is 7.96 Ω.

5 0
4 years ago
Simplify 18 cos Ø (algebra)
ArbitrLikvidat [17]

Answer:

  that's as simple as it gets

Step-by-step explanation:

"Simplify" usually means "combine like terms, rationalize the denominator, reduce radicals to the greatest extent, cancel common factors from fractions, eliminate parentheses," and the like.

When a function of a single variable is multiplied by a single constant, there is no simplification that can be done.

  18cos(Ф)

_____

If your ∅ is supposed to be zero, then cos(0) = 1 and it simplifies to 18.

7 0
4 years ago
Solve <br> f(x)=4x5−8x4+8x2−4x
Goryan [66]

Given:

The function is:

f(x)=4x^5-8x^4+8x^2-4x

To find:

The roots of the given equation.

Solution:

We have,

f(x)=4x^5-8x^4+8x^2-4x

For roots, f(x)=0.

4x^5-8x^4+8x^2-4x=0

4x(x^4-2x^3+2x-1)=0

4x((x^4-1)+(-2x^3+2x))=0

4x((x^2+1)(x^2-1)-2x(x^2-1))=0

On further simplification, we get

4x(x^2+1-2x)(x^2-1)=0

4x(x-1)^2(x+1)(x-1)=0

4x(x+1)(x-1)^3=0

Using zero product property, we get

4x=0

x=0

Similarly,

x+1=0

x=-1

And,

(x-1)^3=0

x=1

Therefore, the zeroes of the given function are -1,0,1 and the factor form of the given function is f(x)=4x(x+1)(x-1)^3.

6 0
3 years ago
What is the range of function from y = 2x - 2 with the domain 1,2,3 ?
algol [13]
If the domain of <span>y = 2x - 2 is {1, 2, 3}, then the range has only three values:

2(1)-2=0
2(2)-2=2
2(3)-2=4

The range is {0,2,4}.</span>
6 0
3 years ago
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