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4 years ago

Is 3x + 2x = 3 a function

Mathematics

1 answer:

worty [1.4K]4 years ago

5 0

Answer:

You need to solve for Y. There should only be one corresponding y-value for that x-value. y = x + 1 is a function because Y is ALWAYS greater then X.

Step-by-step explanation:

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without looking not picking a red hat from a box that holds 20 red hats, 30 blue hats, 15 green hats, and 25 white hats

PolarNik [594]

There are 90 hats all together. from just red the fraction is 20/90. 20 divide by 90 = .22
there is a 22% chance.

5 0

3 years ago

To find the slant height, l, of a cone with a surface area of 500π ft2 and a radius of 15 ft.

Sholpan [36]

The slant height of the cone with the given measurements would be would be around 18.3164 ft.

You can use cone formulas to get to this answer to find the slant height.

I hope this helps :)

3 0

4 years ago

Read 2 more answers

Write the equation of the conic section satisfying the given conditions. focus at the pole, e = 3/4, horizontal directrix 2 unit

hjlf

Answer:

The equation in the polar form is;

$r = \dfrac{6}{4 + 3 \cdot sin(\theta)}$

Step-by-step explanation:

e = 3/4 > 1, we have an hyperbola

The polar equation of a conic is of the form;

For vertical directrix

$r = \dfrac{k \cdot e}{1\pm e \cdot cos (\theta)}$

For horizontal directrix

$r = \dfrac{k \cdot e}{1\pm e \cdot sin(\theta)}$

Where;

k = Distance from the focus to the directrix = 2

We have;

$r = \dfrac{2 \cdot \dfrac{3}{4} }{1 + \dfrac{3}{4} \cdot sin(\theta)}$

$r = \dfrac{\dfrac{3}{2} }{1 + \dfrac{3}{4} \cdot sin(\theta)}$

Which gives the equation in the polar form as follows;

$r = \dfrac{6}{4 + 3 \cdot sin(\theta)}$ .

8 0

3 years ago

Olivia bought a beach towel for $9.95 and a beach bag for $13.46. What is the total amount of money Olivia spent on the two item

USPshnik [31]

Answer:

$23.41

Step-by-step explanation:

$9.95 + $13.46 = $23.41

5 0

4 years ago

If a polynomial function f(x) has roots 3+root5 and -6, what must be a factor of f(x)? (X+(3-root5) (x-(3-root5)) (x+(5+root3))

belka [17]

Answer:

$(x-(3+\sqrt5))$ or $(x-3-\sqrt5)$ is a factor of the given polynomial.

Step-by-step explanation:

Let us learn the concept with an example first.

Let the polynomial be a quadratic function $g(x)$ .

$g(x) = x^{2} -5x+6$

The roots of $g(x)$ are 2 and 3.

Putting $x= 2\ in \ g(x)$

$2^2-5\times 2+6 = 4-10+6 =0$

Putting $x= 3\ in \ g(x)$

$3^2-5\times 3+6 = 9-15+6 =0$

Putting x = 2 or x = 3, g(x) = 0 $\therefore$ The roots of equation g(x) are 2 and 3.

Now, let us try to factorize g(x):

$x^{2} -2x-3x+6\\\Rightarrow x(x -2)-3(x-2)\\\Rightarrow (x-3)(x-2)$

so, the equation can be written as:

$g(x) = x^{2} -5x+6=(x-3)(x-2)$ where 3 and 2 are the roots of equation.

The factors are (x-3) and (x-2).

$\therefore$ for the polynomial f(x) which has roots $3+\sqrt5\ and\ -6$ will have a factor:

$(x-(3+\sqrt5))$ or $(x-3-\sqrt5)$

8 0

4 years ago