Question

If f(x)=7x-3 and g(x)=x^2-4x-8, Find (f+g)(x)

Answer 1

For this case we have the following functions:

$f (x) = 7x-3\\g (x) = x ^ 2-4x-8$

We must find $(f + g) (x):$

By definition we have to:

$(f + g) (x) = f (x) + g (x)\\(f + g) (x) = 7x-3 + x ^ 2-4x-8$

We add similar terms, taking into account that equal signs are added and the same sign is placed, while different signs are subtracted and the sign of the major is placed.

$(f + g) (x) = x ^ 2 + 3x-11$

Answer:

$(f + g) (x) = x ^ 2 + 3x-11$

Answer 2

Answer:

Step-by-step explanation:

The value of (f+g)(x) is x^2 + 3x - 11

You can combine this by simply adding the like terms. Start by adding together all of the x^2 terms. Since only g(x) has one of those, we use that in its entirety.

x^2

Next we add together the x terms. f(x) has 7x and g(x) has -4x.

7x + -4x = 3x

Finally, we add together the constants. f(x) has -3 and g(x) has -8.

-3 + -8 = -11

With all of the like terms combined, we simply take the answers and put them together.

x^2 + 3x - 11

Read more on Brainly.com - brainly.com/question/10711144#readmore